All categories

4 years ago

Which are long chains of subunits formed by the process of polymerization? Check all that apply.

Physics

2 answers:

Leya [2.2K]4 years ago

8 0

B,D,F just took the test

vampirchik [111]4 years ago

6 0

The long chains of subunits formed by the process of polymerization are:

B. Macromolecules

D. Polymers

F. DNA

You might be interested in

A coil 3.95 cm radius, containing 520 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×1

Pie

Answer:

(a) E= 3.36×10−2 V +( 3.30×10−4 V/s3 )t3

(b) $I=0.0085\ A$

Explanation:

Given:

radius if the coil, $r=0.0395\ m$

no. of turns in the coil, $n=520$

variation of the magnetic field in the coil, $B=(1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4$

resistor connected to the coil, $R=560\ \Omega$

(a)

we know, according to Faraday's Law:

$emf=n.\frac{d\phi}{dt}$

where:

$d \phi=$ change in associated magnetic flux

$\phi= B.A$

where:

A= area enclosed by the coil

Here

$A=\pi.r^2$

$A=\pi\times 0.0395^2$

$A=0.0049\ m^2$

$\therefore \phi=((1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)\times 0.0049$

So, emf:

$emf= 520\times \frac{d}{dt} [((1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)\times 0.0049]$

$emf= 520\times 0.0049\times \frac{d}{dt} [(1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)]$

$emf= 2.548\times [0.012+(13.8\times 10^{-5})t^3)]$

$emf= 0.0306+3.516\times 10^{-4}\ t^3$

(b)

Given:

$t_0=5.25\ s$

Now, emf at given time:

$emf=4.7755\times 10^{-2}\ V$

∴Current

$I=\frac{emf}{R}$

$I=\frac{4.7755\times 10^{-2}}{560}$

$I=8.5\times 10^{-5} A$

6 0

4 years ago

une lampe soumise à une tension continue de 12V , consomme unepuissance de 1.8 W. L'intensité du courant traversant la lampe est

Eduardwww [97]

Answer:

I = 0.15 A

Explanation:

The question is "a lamp subjected to a continuous voltage of 12V , consumes a power of 1.8 W. The intensity of the current passing through the lamp is what"

Given that,

Power of the lamp, P = 1.8 W

Voltage, V = 12 V

We need to find the current through the lamp. The power of the lamp is given by :

$P=V\times I\\\\I=\dfrac{P}{V}\\\\I=\dfrac{1.8}{12}\\\\I=0.15\ A$

So, the current through the lamp is 0.15 A.

6 0

3 years ago

PLLLLLLLLLZ HELP 30 POINTS ANSWER ONLY IF YOU KNOW

Karo-lina-s [1.5K]

Answer:

R^2 = 40^2 + 70^2 - 2(40)(70) cos 135°

Explanation:

The resultant connects the tail of the first vector to the head of the second vector (whose tail is at the head of the first vector). The three vectors form an obtuse triangle where the angle between the original direction and the second direction is 135°. The cosine factor in the Law of Cosines formula will be cos(135°), matching the second choice.

4 0

3 years ago

It takes fifteen minutes to complete a drilling operation using a lathe. the duration of this operation is known as _____ time.

dalvyx [7]

I think the correct answer would be processing time. The time of fifteen minutes describes how long the whole operation was done or how long is the whole processing of drilling. Hope this answers the question. Have a nice day.

8 0

4 years ago

When an 80.0-kg man stands on a pogo stick, the spring is compressed 0.120 m. (a) What is the force constant of the spring? (b)

Nimfa-mama [501]

Answer:

a.6533.333 N/m

b.Yes,the spring will be compressed more when the person hops down the road .

Explanation:

Mass of man=80 kg

Spring compressed by x=0.12 m

a.We have to find the force constant of the spring.

Spring constant= $k=\frac{F}{x}=\frac{mg}{x}$

$g=9.8m/s^2$

Using the formula

Spring constant, $k=\frac{80\times 9.8}{0.12}$ N/m

Spring constant= $k=6533.33 N/s$

b.The spring will be compressed more when the person hops down the road because when the person hops down then the kinetic energy of person will be converted into potential energy during the road hit.

7 0

3 years ago