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3 years ago

Which are long chains of subunits formed by the process of polymerization? Check all that apply.

Physics

2 answers:

Leya [2.2K]3 years ago

8 0

B,D,F just took the test

vampirchik [111]3 years ago

6 0

The long chains of subunits formed by the process of polymerization are:

B. Macromolecules

D. Polymers

F. DNA

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Robin Hood wishes to split an arrow already in the bull's-eye of a target 40 m away.

tamaranim1 [39]

Answer:

5.843 m

Explanation:

suppose that the arrow leave the bow with a horizontal speed , towards he bull's eye.

lets consider that horizontal motion

distance = speed * time

time = 40/ 37 = 1.081 s

arrow doesnot have a initial vertical velocity component. but it has a vertical motion due to gravity , which may cause a miss of the target.

applying motion equation

(assume g = 10 m/s²)

$s=ut+\frac{1}{2}*gt^{2} \\= 0+\frac{1}{2}*10*1.081^{2}\\= 5.843 m$

Arrow misses the target by 5.843m ig the arrow us split horizontally

4 0

2 years ago

The thermal energy used by heater in 3 minutes is used to melt wax.Melting point of solid wax is 60.Specific heat of wax is 220j

Romashka-Z-Leto [24]

Answer:

m = 35 g

Explanation:

The specific heat of a material can be calculated by the following formula:

$C = \frac{Q}{m}\\$

where,

C = Specific Heat of Wax = 220 J/g

Q = Amount of Heat Supplied by the Heater = 7700 J

m = mass of wax melted = ?

Therefore,

$220\ J/g = \frac{7700\ J}{m}\\\\m = \frac{7700\ J}{220\ J/g}\\$

5 0

2 years ago

What is the acceleration of an 24 kg object that applies a force of 130N?

WITCHER [35]

Answer:

To find the acceleration of the object we have to apply Newton second law of motion that is F = mass × acceleration.

Explanation:

Given ,

F = 130N

M = 24kg

A = ?

F = m× a

then ,

130N = 24kg ×a

a = 130/24 = 5 m/s.

6 0

1 year ago

A child standing on a bus remains still when the bus is at rest. When the bus moves forward and then slows down, the child conti

expeople1 [14]

Newton's first law of motion

3 0

2 years ago

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A box is at rest on a ramp at an incline of 22°. The normal force on the box is 538 N.

fomenos

Answer: 580 N

Refer to attached figure.

The angle of inclination is 22 degrees

weight (gravitational force) acts downwards.

Normal force is a contact force which acts perpendicular to the point of contact.

The horizontal component (mg cos 22 ) balances the normal force and the vertical component balances the frictional force.

Gravitational force on an object = mg

The normal force $N= mg cos 22$

$\Rightarrow mg =\frac{N}{cos22}=\frac{538 N}{0.927}=580 N$

8 0

3 years ago

Read 2 more answers