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3 years ago

I was an American inventor and businessman who is best known for inventing the electric light bulb. Who am I?

2 answers:

6 0

The one man, who was famous and was also known for inventing the electric light bulb..was the one and only...Thomas Edison!!!

wel3 years ago

4 0

You are Thomas Alva Edison. You also invented the phonograph
and the first practical movie camera. Sadly, you died almost exactly
9 years before I was born.

You might be interested in

Entropy is how quickly things get messy. O A. True OB. False Answer : False

Anarel [89]

Answer:

false

Explanation:

it cant defined the messy and clean states

5 0

2 years ago

An object is swung in a horizontal circle on a length of string that is 0.93 m long. Its acceleration is 26.36 m/s2. What is the

Igoryamba

Answer:

The object takes approximately 1.180 seconds to complete one horizontal circle.

Explanation:

From statement we know that the object is experimenting an Uniform Circular Motion, in which acceleration ( $a$ ), measured in meters per square second, is entirely centripetal and is expressed as:

$a = \frac{4\pi^{2}\cdot R}{T^{2}}$ (1)

Where:

$T$ - Period of rotation, measured in seconds.

$R$ - Radius of rotation, measured in meters.

If we know that $a = 26.36\,\frac{m}{s^{2}}$ and $R = 0.93\,m$ , then the time taken by the object to complete one revolution is:

$T^{2} = \frac{4\pi^{2}\cdot R}{a}$

$T = 2\pi\cdot \sqrt{\frac{R}{a} }$

$T = 2\pi\cdot \sqrt{\frac{0.93\,m}{26.36\,\frac{m}{s^{2}} } }$

$T \approx 1.180\,s$

The object takes approximately 1.180 seconds to complete one horizontal circle.

7 0

3 years ago

How long do congressional terms last

zhannawk [14.2K]

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7 0

4 years ago

Point charges q1=+2.00μC and q2=−2.00μC are placed at adjacent corners of a square for which the length of each side is 5.00 cm.

8_murik_8 [283]

The electric potential is a scalar unit, so we don't have to struggle with the vectors. The formula that gives electric potential is

$V = \frac{1}{4\pi\epsilon_0}\frac{q}{r}$

1) At point a, the electric potential is the sum of the potentials due to q1 and q2. So,

$V_a = \frac{1}{4\pi\epsilon_0}\frac{q_1}{r_1} + \frac{1}{4\pi\epsilon_0}\frac{q_2}{r_2}$

The distance from the center of the square to one of the corners is $\sqrt2 L/2 = 0.035m$

$V_a = \frac{1}{4\pi\epsilon_0}\frac{2\times10^{-6}}{0.035} + \frac{1}{4\pi\epsilon_0}\frac{-2\times10^{-6}}{0.035} = 0$

The answer is zero, because the point charges are at equal distances and their magnitudes are also equal but their directions are opposite.

2) $V_b = \frac{1}{4\pi\epsilon_0}\frac{q_1}{r_1} + \frac{1}{4\pi\epsilon_0}\frac{q_2}{r_2}$

$r_1 = 0.05\sqrt2m\\r_2 = 0.05m$

$V_b = \frac{1}{4\pi\epsilon_0}\frac{2\times10^{-6}}{0.05\sqrt2} + \frac{1}{4\pi\epsilon_0}\frac{-2\times10^{-6}}{0.05}\\V_b = \frac{1}{4\pi\epsilon_0}\frac{2\times10^{-6}}{0.05} (\frac{1}{\sqrt2}-1)\\V_b = \frac{1}{4\pi\epsilon_0} (4\times 10^{-5})(-0.29)\\V_b = (-\frac{2.9\times10^{-6}}{\pi\epsilon_0})[tex]3) The work done on q3 by q1 and q2 is equal to the difference between energies. This is the work-energy theorem. So,[tex]W = U_b - U_a$

$U = \frac{1}{4\pi\epsilon_0}\frac{q_1q_3}{r} = Vq_3$

$W = q_3(V_b - V_a) = q_3(V_b - 0)\\W = (-2\times10^{-6})(-\frac{2.9\times10^{-6}}{\pi\epsilon_0})\\W = \frac{5.8\times10^{-12}}{\pi\epsilon_0}$

4 0

3 years ago

A wave with 2.0 m amplitude has a frequency of 500 Hz is travelling at a speed of 200 m/s. What is the wavelength?

Serggg [28]

Answer: 0.4m

Explanation:

Given that:

Amplitude of wave = 2.0 m

Wavelength (λ)= ?

Frequency F = 500Hz

Speed V = 200 m/s

The wavelength is measured in metres, and represented by the symbol λ.

So, apply the formula:

Wavespeed V= Frequency F xwavelength λ

200m/s = 500Hz x λ

λ = 200m/s / 500Hz

λ = 0.4m

Thus, the wavelength is 0.4 metres

3 0

3 years ago