1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
uranmaximum [27]
2 years ago
15

What occurs in electroplating?

Chemistry
1 answer:
mixas84 [53]2 years ago
5 0
I think it’s the first one. Electroplating means you put on a layer of metal on something.
You might be interested in
Is Lilium lancifolium Heterotroph, Autotroph, or Both
Sphinxa [80]
Lilium lancifolium is an autotroph since it is a plant and makes its own food through photosynthesis.
4 0
2 years ago
What type of charge does each part of an atom have (positive, negative, no charge)
Masteriza [31]
Answer:
P-positive
N-negative
E-no charge
6 0
2 years ago
Read 2 more answers
How many atoms of each element are in one molecule of this product.
anastassius [24]
I assume about 5 atoms are in one molecule of this product
7 0
3 years ago
Molybdenum (Mo) has a body centered cubic unit cell. The density of Mo is 10.28 g/cm3. Determine (a) the edge length of the unit
ser-zykov [4K]

<u>Answer:</u>

<u>For a:</u> The edge length of the unit cell is 314 pm

<u>For b:</u> The radius of the molybdenum atom is 135.9 pm

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the edge length for given density of metal, we use the equation:

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density = 10.28g/cm^3

Z = number of atom in unit cell = 2  (BCC)

M = atomic mass of metal (molybdenum) = 95.94 g/mol

N_{A} = Avogadro's number = 6.022\times 10^{23}

a = edge length of unit cell =?

Putting values in above equation, we get:

10.28=\frac{2\times 95.94}{6.022\times 10^{23}\times (a)^3}\\\\a^3=\frac{2\times 95.94}{6.022\times 10^{23}\times 10.28}=3.099\times 10^{-23}\\\\a=\sqrt[3]{3.099\times 10^{-23}}=3.14\times 10^{-8}cm=314pm

Conversion factor used:  1cm=10^{10}pm  

Hence, the edge length of the unit cell is 314 pm

  • <u>For b:</u>

To calculate the edge length, we use the relation between the radius and edge length for BCC lattice:

R=\frac{\sqrt{3}a}{4}

where,

R = radius of the lattice = ?

a = edge length = 314 pm

Putting values in above equation, we get:

R=\frac{\sqrt{3}\times 314}{4}=135.9pm

Hence, the radius of the molybdenum atom is 135.9 pm

4 0
3 years ago
The number of molecules in 1.0 mole of H2O is the same as in one mole of O2.
zaharov [31]
True. A mole of anything has the same amount of molecules. 1 mole = 6.022 x 1023 molecules 
8 0
3 years ago
Read 2 more answers
Other questions:
  • In the periodic table below, shade all the elements for which the neutral atom has a valence electron configuration of ns2np3 ,
    11·1 answer
  • 0which carbohydrate provides energy for cows but only dietary fiber for humans
    10·1 answer
  • Calculate the mass percent of titanium in the mineral ilmenite, FeTiO3. What mass of ilmenite (in grams) is required if you wish
    9·1 answer
  • A gas that has a volume of 28 liters, a temperature of 45 0 C, and an unknown pressure has its volume increased to 34 liters and
    7·1 answer
  • Where do Alkanes come from​
    15·1 answer
  • Explain why, if soil on a vehicle is in a clump, care<br> should be taken to keep the clump intact.
    15·1 answer
  • In metallic bonds, the mobile electrons surrounding the positive ions are called a(n)
    9·1 answer
  • Helppp nowwww plsss!!!
    15·1 answer
  • What do you think is the primary reason why the Unionid mussel population declined whenever there is a dramatic increase in the
    5·1 answer
  • 62. A substance breaks down into its component elements
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!