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Soloha48 [4]
3 years ago
8

Which equation agrees with the ideal gas law? V V2 OTT O V. = V202 o Pina = P212

Chemistry
1 answer:
OLEGan [10]3 years ago
7 0
<h2>The equation that  agrees with the ideal gas law: None of it </h2>

Explanation:

None , of the given equation goes with the ideal gas law .

Ideal gas law

It is the law that gives the relationship between P,V,T and number of moles .

Ideal gas equation

It is the law that is formed by combining Boyle's law , charle's law ,Avgadro's  law that is :

P ∝ 1/v

V∝T

V∝n

combining all, we get

PV=nRT

where R is a gas constant .

This is an ideal gas equation ,

  • The first option given : V₁/T₁=V₂/T₂
  • The second option : V₁n₁=V₂n₂
  • The third equation : P₁n₁=P₂n₂
  • The fourth option : P₁/T₁=P₂/T₂

none ,of it specifies because ideal gas equation relation is :

P₁V₁/T₁=P₂V₂/T₂ is an ideal gas equation

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fomenos

Answer: CaCO_3 is a reactant; it is present before the reaction occurs.

Explanation:

In a chemical reaction the chemical formulas written before the arrow are described as reactants as they react together to form products which are written after the arrow.

CaCO_3 + 2HCl \rightarrow CaCl_2 + CO_2 + H_2O

Thus CaCO_3 and HCl are reactants here whereas CO_2, CaCl_2 and H_2O are products.

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What volume would 0.853 moles of Nitrogen gas occupy at STP?
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Answer:

19.12 L

Explanation:

At STP(i.e. Standard temperature and pressure).

The volume occupied by one mole of gas = 22.4 L

The pressure = 1 atm

The temperature = 273 K

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6 0
3 years ago
Can you help me with this with a solution
LuckyWell [14K]

The complete table is inserted.

A table is given,

Formulas used:

pH=  -log(H⁺)

pOH=  -log(OH⁻)

pH+ pOH=14

Calculations:

For A: (H⁺)=2×10⁻⁸M

Using the pH formula:

pH=  -log(H⁺)=-log(2×10⁻⁸)=7.69

pOH=14 - 7.69=6.3

Calculating OH concentration,

pOH=  -log(OH⁻)

6.3= -log(OH⁻)

(OH⁻)=5.011×10⁻⁷M

Hence, the nature of A is basic.

Similarily,

For B,

(OH⁻)=1×10⁻⁷

Using the pH formula:

pOH=  -log(OH⁻)= -log(1×10⁻⁷)=7

pH=14-7=7

Calculating H concentration,

pH=  -log(H⁺)

7= -log(H⁺)

(H⁺)=1×10⁻⁷M

Hence, the nature of B is neutral.

Similarily,

For C,

pH=12.3

Using the pH formula:

pOH=14-12.3=1.7

Calculating H concentration,

pH=  -log(H⁺)

12.3= -log(H⁺)

(H⁺)=5.011×10⁻¹³M

Calculating OH concentration,

pOH=  -log(OH⁻)

1.7= -log(OH⁻)

(OH⁻)=1.99×10⁻²M

Hence, the nature of C is Basic.

Similarily,

For D,

pOH=6.8

Using the pH formula:

pH=14-6.8=7.2

Calculating H concentration,

pH=  -log(H⁺)

7.2= -log(H⁺)

(H⁺)=6.309×10⁻⁸M

Calculating OH concentration,

pOH=  -log(OH⁻)

6.8= -log(OH⁻)

(OH⁻)=1.58×10⁻⁷M

Hence, the nature of D is basic.

Learn more about the acid and bases here:

brainly.com/question/16189013

#SPJ10

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Answer:

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The image depicts the atoms of two different elements; atoms of lighter and heavier elements.

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⇒ As the weight increases, the rate of diffusion (movement of atoms) decreases.

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The image is not accurate because

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but the lighter ones must move faster than the heavier ones.

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