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3 years ago

Which equation agrees with the ideal gas law? V V2 OTT O V. = V202 o Pina = P212

Chemistry

1 answer:

OLEGan [10]3 years ago

7 0

<h2>The equation that agrees with the ideal gas law: None of it </h2>

Explanation:

None , of the given equation goes with the ideal gas law .

Ideal gas law

It is the law that gives the relationship between P,V,T and number of moles .

Ideal gas equation

It is the law that is formed by combining Boyle's law , charle's law ,Avgadro's law that is :

P ∝ 1/v

V∝T

V∝n

combining all, we get

PV=nRT

where R is a gas constant .

This is an ideal gas equation ,

The first option given : V₁/T₁=V₂/T₂
The second option : V₁n₁=V₂n₂
The third equation : P₁n₁=P₂n₂
The fourth option : P₁/T₁=P₂/T₂

none ,of it specifies because ideal gas equation relation is :

P₁V₁/T₁=P₂V₂/T₂ is an ideal gas equation

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A 10.00 g sample of a soluble barium salt is treated with an excess of sodium sulfate to precipitate 11.21 g BaSO4 (M- 233.4). W

aliina [53]

Answer:

The salt is barium chloride.

Explanation:

$BaX_2++Na_2SO_4\rightarrow BaSO_4+2NaX$

Moles of barium sulfate = $\frac{11.21 g}{233.38 g/mol}=0.0480 mol$

According to reaction, 1 mol of barium sulfate is produced from 1 mol of $BaX_2$ .

Then 0.0480 moles will be produced from:

$\frac{1}{1}\times 0.0480 mol=0.0480 mol$ of $BaX_2$ .

Mass of $BaX_2$ used = 10.00 g

Moles of $BaX_2$ =\frac{10.00 g}{\text{Molar mass}}[/tex]

$0.0480 mol=\frac{10.00}{\text{Molar mass}}$

Molar mass of $BaX_2$ = 208.33 g/mol

The nearest answer to our answer is $BaCl_2=208.2 g/mol$ .

The correct answer barium chloride with molar mass of 208.2 g/mol.

8 0

3 years ago

The volume of 7.91 M HCl needed to make 196.1 mL of 2.13 M HCl is ____.

Alona [7]

Answer:

a. 52.8

Explanation:

To find the number of moles of HCl we use the relation M₁V₁=M₂V₂

where M₁ is the initial molarity, M₂ the new molarity, V₁ the initial volume used, and V₂ the final volume obtained.

M₁=7.91 M

M₂=2.13 M

V₁=?

V₂=196.1 mL

Replacing these values in the relationship.

M₁V₁=M₂V₂

7.91 M× V₁=2.13 M×196.1 mL

V₁=(2.13 M×196.1 mL)/7.91 M

=52.8 mL

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Answer:

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Explanation:

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