Answer:
Oxygen is the limiting reactant
Explanation:
2H2 + O2 ⇒ 2H2O
2mol 1mol 2mol
2moles of hydrogen will require 1mol of oxygen to produce 2mol of water
in the question, 6.45g of O2 reacts with 1.13g of H2.
molar mass of O2 = 16*2 =32g/mol
molar mass of H2 = 1*2=2g/mol
number of moles of O2 = mass/molar mass
= 6.45/32
=0.20156moles
number of moles of H2 = 1.13/2
=0.565moles
but 0.20156moles of O2 will require 0.40312moles of hydrogen
2H2 + O2 ⇒ 2H2O
2mol 1mol 2mol
0.40312mole 0.20156mol
0.40312moles is less than 0.565moles of H2 present, which means hydrogen is in excess hence implying that oxygen is the limiting reactant
Answer:
last one is the correct and most suitable option.
Hope it helps!!!
Answer:
no ,its not necessary tht two objects have same volume have the same mass because the density of the material they are made up of can be different. mass and volume areindependent, two objects with thesame volume can have differentmasses. Therefore, the objects can have different densities.
Answer:
THE PARTIAL PRESSURE OF OXYGEN GAS IN THE CONTAINER IS 92.67kPa WHICH IS OPTION B.
Explanation:
To calculate the partial pressure of oxygen gas collected over water, we use
Ptotal = Poxygen + P water
It is worthy to note that when oxygen is collected over water, it is mixed with water vapor and the total pressure in the container will be the sum of the pressure exerted by the oxygen gas and that of the water vapor at that given temperature.
At 20 C, the vapor pressure of water as given in the question is 2.33 kPa.
Using the above formula,
Ptotal = Poxygen + P water
Substituting for Poxygen, we have;
Poxygen = Ptotal - P water vapor
P oxygen = 95 .00 kPa - 2.33 kPa
P oxygen = 92.67 kPa.
The partial pressure of oxygen gas in the container is hence, 92.67kPa.
Answer:
If you mean the number of atoms in 8g of oxygen, it's 3.011 x 10^23 atoms.
Explanation:
Convert the grams to moles. 8 grams of oxygen is 0.5 moles. Then multiply the number of moles by Avogadro's number: 6.022 x 10^23.
