Answer:
Use the right-hand rule for magnetic force to determine the charge on the moving particle.
This is a
negative
charge
Explanation:
Answer:hiuwiauwney jejjksuu
Explanation:
Answer:
a. 4.9 m
Explanation:
To solve this problem we must take into account that power is defined as the relationship between the work and the time in which the work is done.
P = W/t
where:
P = power = 95 [W] (units of watts)
W = work [J] (units of Joules)
t = time = 6.2 [s]
We can clear the work from the previous equation.
W = P*t
W = 95*6.2 = 589 [J]
Now we know that the work is defined by the product of the force by the distance, therefore we can express the work done with the following equation.
W = F*d
where:
F = force = 120 [N] (units of Newtons)
d = distance [m]
d = W/F
d = 589/120
d = 4.9 [m]
Answer:
I would increase the horizontal velocity or the vertical velocity or both to make the ball go the extra distance to cross the goal line.
Explanation:
In order to increase the horizontal distance covered by the ball, we need to examine the variables involved in the formula of range of projectile. The formula for the range of projectile is given as follows:
R = V₀² Sin 2θ/g
where, g is a constant on earth (acceleration due to gravity) and θ is the angle of ball with ground at the time of launching. The value of θ should be 45° for maximum range. In this case we do not know the angle so, we can not tell if we should change it or not.
The only parameter here which we can increase to increase the range is launch velocity (V₀). The formula for V₀ in terms of horizontal and vertical components is as follows:
V₀ = √(V₀ₓ² + V₀y²)
where,
V₀ₓ = Horizontal Velocity
V₀y = Vertical Velocity
Hence, it is clear from the formula that we can increase both the horizontal and vertical velocity to increase the initial speed which in turn increases the horizontal distance covered by the ball.
<u>Therefore, I would increase the horizontal velocity or the vertical velocity or both to make the ball go the extra distance to cross the goal line.</u>
