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goldenfox [79]
4 years ago
7

Which facility relies on a no renewable source of energy

Physics
1 answer:
Rainbow [258]4 years ago
4 0

Answer:

Coal

Explanation:

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The tortoise and the hare are having a race over a course of length 0.52 km. The tortoise crawls along at a constant 0.075 m/s w
EastWind [94]

Answer:the hare slept for 1 hr 55minutes.

Explanation: distance is changed to meters = 520m

Speed=distance/time

Speed of tortoise is 0.075m/s=520m/t

Crops multiplying t= 520/0.075 = 6933.3 seconds.

Speed for hare 16.7m/s =260m/t

ie 260m is half of the distance.

t =15.56seconds

Therefore the time slept by the hare = 6933.3- 15.56= 6917.74 seconds.

Converting to hours = 1hr. 55minutes is the time the hare slept.

3 0
3 years ago
Which term describes the motion of gas particles?
levacccp [35]
2. random motion in vertical direction
6 0
3 years ago
Read 2 more answers
Why is AU (astronomical unit) the unit of distance that we used instead of kilometers?
Novay_Z [31]

Answer:

The solar system is enormous, and interstellar space is even bigger. One astronomical unit is equal to 150 million kilometers. This makes it much easier to count the distances if they're in counts of Astronomic Units instead of having to count everything in millions or billions of kilometers

Explanation:

7 0
4 years ago
A hydrogen atom Is In Its ground state when Its orbital electron is what
cricket20 [7]

Answer: K-core , 1s orbital

Explanation:  Electron of Hydrogen atom has lowest energy

when it is in K core (1s-orbital)

8 0
3 years ago
A mass with mass 4 is attached to a spring with spring constant 24 and a dashpot giving a damping 20. The mass is set in motion
aleksandrvk [35]

Answer: x(t) = 14e^{-2t} - 10e^{-3t}

Explanation: In a mass-spring-damper system, the differential equation that rules the motion of the mass is: mx" + cx' + kx = 0

Using m = 4, k = 24 and c = 20, we have

4x" + 20x' + 24x = 0

Simplifying, we have

x" + 5x'+ 6x = 0

The characteristic equation of this differential is

r^{2} + 5r + 6 = 0

The solutions for the quadratic equation are: r_{1} = -2 and r_{2} = -3

Hence:

x(t) = C_{1}e^{-2t} + C_{2}e^{-3t}

x'(t) = -2C_{1}E^{-2t} - 3C_{2}e^{-3t}

To determine the constants, we have the initial conditions x(0) = 4 and

x'(0) = 2, then:

x(0) = C_{1} + C_{2} = 4\\          C_{1} = 4 - C_{2}

x'(0) = -2C_{1} -3C_{2} = 2\\-2(4-C_{2}) -3C_{2} = 2\\C_{2} = -10\\C_{1} = 4 - C_{2}\\C_{1} = 14

Substituing the constants:

x(t) = 14e^{-2t} - 10e^{-3t}

The position function for this system is: x(t) = 14e^{-2t} - 10e^{-3t}

7 0
3 years ago
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