Answer:
68,2%
Explanation:
Supposing the initial salt concentration of lake Parsons is the same of non-isolated lakes, 6,67L, and the change of salt concentration in isolated lake is just for water evaporation it is possible to write:
6,67gL⁻¹×X = 21gL⁻¹×Y
<em>-Where X is the initial water and Y is the water that remains in the isolated lake-</em>
Thus:
6,67X = 21Y
0,318 = Y/X
0,318 is the ratio of water that remains between total water. To obtain the ratio of evaporated water:
1-0,318 = 0,682
In percentage: <em>68,2%</em>
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I hope it helps!
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I think it's reactivity. but i'm not sure.
1 in 10, or 1/10, or 0.1 dilution factor It may be wrong but this is what I have!
Answer:
Solute concentration will afect the rate of a chemical reaction, because you must work with molarity
Explanation:
I think that solute mass may be it can affect the rate of reaction, if you have more mass in a solute, you will also have more moles.
If you want to know more, you have to consider temperature in the reaction and the presence of catalysts. They all, affect reactions.