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Lorico [155]
3 years ago
5

The acidic substance in vinegar is acetic acid, HC2H3O2 When 4.00 g of a certain vinegar sample was titrated with 0.200 M NaOH,

25.56 mL of the NaOH solution were required to reach the equivalence point. What is the mass percent of HC2H3O2in the vinegar?
Chemistry
1 answer:
Vika [28.1K]3 years ago
8 0

Answer:

7.68%

Explanation:

Let's consider the neutralization reaction between acetic acid and sodium hydroxide.

HC₂H₃O₂ + NaOH → NaC₂H₃O₂ + H₂O

25.56 mL of 0.200 M NaOH reacted. The reacting moles of NaOH are:

0.02556 L × 0.200 mol/L = 5.11 × 10⁻³ mol

The molar ratio of HC₂H₃O₂ to NaOH is 1:1. The reacting moles of HC₂H₃O₂ are 5.11 × 10⁻³ moles.

The molar mass of acetic acid is 60.05 g/mol. The mass corresponding to 5.11 × 10⁻³ moles is:

5.11 × 10⁻³ mol ×  60.05 g/mol = 0.307 g

0.307 g of acetic acid are in 4.00 g of vinegar. The mass percent of HC₂H₃O₂ is:

0.307 g/4.00 g × 100% = 7.68%

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Explanation:

Supposing the initial salt concentration of lake Parsons is the same of non-isolated lakes, 6,67L, and the change of salt concentration in isolated lake is just for water evaporation it is possible to write:

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<em />

I hope it helps!

<em />

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