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Lorico [155]
3 years ago
5

The acidic substance in vinegar is acetic acid, HC2H3O2 When 4.00 g of a certain vinegar sample was titrated with 0.200 M NaOH,

25.56 mL of the NaOH solution were required to reach the equivalence point. What is the mass percent of HC2H3O2in the vinegar?
Chemistry
1 answer:
Vika [28.1K]3 years ago
8 0

Answer:

7.68%

Explanation:

Let's consider the neutralization reaction between acetic acid and sodium hydroxide.

HC₂H₃O₂ + NaOH → NaC₂H₃O₂ + H₂O

25.56 mL of 0.200 M NaOH reacted. The reacting moles of NaOH are:

0.02556 L × 0.200 mol/L = 5.11 × 10⁻³ mol

The molar ratio of HC₂H₃O₂ to NaOH is 1:1. The reacting moles of HC₂H₃O₂ are 5.11 × 10⁻³ moles.

The molar mass of acetic acid is 60.05 g/mol. The mass corresponding to 5.11 × 10⁻³ moles is:

5.11 × 10⁻³ mol ×  60.05 g/mol = 0.307 g

0.307 g of acetic acid are in 4.00 g of vinegar. The mass percent of HC₂H₃O₂ is:

0.307 g/4.00 g × 100% = 7.68%

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2 years ago
Kepler and Newton studied the movement of planets. Kepler studied the speed of the planets while Newton studied the forces that
nasty-shy [4]
Kepler did not study the speed of the planets, rather, he studied how the planets move in the solar system. He proposed three laws. As a summary, he described that the planets move around the sun in the shape of an ellipse (orbit), and the Sun being one of the foci. Then, he proposed the period for the planet to complete one revolution around the Sun. 

On the other hand, Newton studied the forces acting on the planet (or any object in space) that explain how the planets move around the solar system as described by Kepler. Also, Kepler's observations only apply to planets and not the moons or satellites. Thus, Kepler only made laws from observations, while Newton based it from underlying principles that led him to mathematical equations such as the law of universal gravitation.
4 0
3 years ago
Read 2 more answers
How many L of a 7.5 H2SO4 stock solution would you need to prepare a dilute solution 100 L of 0.25M H2SO4
blsea [12.9K]

Answer:

3.33 L

Explanation:

We can solve this problem by using the equation:

  • C₁V₁=C₂V₂

Where the subscript 1 refers to one solution and subscript 2 to the another solution, meaning that in this case:

  • C₁ = 0.25 M
  • V₁ = 100 L
  • C₂ = 7.5 M
  • V₂ = ?

We input the data:

  • 0.25 M * 100 L = 7.5 M * V₂
  • V₂ = 3.33 L

Thus the answer is 3.33 liters.

3 0
2 years ago
He reaction produces 1.6 g of gas in 30 seconds.Calculate the mean rate of the reaction in the first 30 seconds.Use the equation
devlian [24]

Answer:

Mean rate of reaction produced = 0.533 g/sec (approx.)

Explanation:

Given:

Reaction produced = 1.6 gram

Time taken = 30 sec

Find:

Mean rate of reaction produced

Computation:

Mean rate of reaction produced = Reaction produced / Time taken

Mean rate of reaction produced = 1.6 / 30

Mean rate of reaction produced = 0.533 g/sec (approx.)

5 0
3 years ago
Please help
ludmilkaskok [199]

Answer: The molecular formula will be C_3H_9

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.  

The empirical formula is CH_3

The empirical weight of CH_3 = 1(12)+3(1)= 15g.

The molecular weight = 45.0 g/mole

Now we have to calculate the molecular formula:

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{45}{15}=3

The molecular formula will be=3\times CH_3=C_3H_9

Thus molecular formula will be C_3H_9

6 0
3 years ago
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