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3 years ago

When electric and magnetic fields both exist, it is called a(n) ___________ field

Physics

2 answers:

mafiozo [28]3 years ago

5 0

Answer:

Electromagnetic!

Explanation:

When they both meet they bring electromagnetic fields into play.

Glad I was able to help!!

arlik [135]3 years ago

3 0

Answer:

electromagnetic field

Explanation:

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A vw bug is driving north on a straight two lane road at a constant 54 mph and chevy impala south at 47 on the same road (but di

mario62 [17]

Velocity of vw bug is given as

$v_1 = 54 mpH$ towards north

velocity of imphala is given as

$v_2 = 47 mph$ towards south

now we need to find velocity of imphala relative to bug

$v_{21} = v_2 - v_1$

$v_{21} = 47 - (-54) = 101 mpH$

so the speed is 101 mpH towards south so correct option is C

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3 years ago

Work is NOT done by a person when she?

garik1379 [7]

Answer:

I think it is pulling the sled off the ice covered back yard.

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2 years ago

If 2.0×10^−4 C of charge passes a point in 2.0×10^−6 s , what is the rate of current flow?1.0×10^−10 A1.0×10^2 A4.0×10^−1 A4.0×1

Ipatiy [6.2K]

This problem is about the rate of the current. It's important to know that refers to the quotient between the electric charge and the time, that's the current rate.

$I=\frac{Q}{t}$

Where Q = 2.0×10^−4 C and t = 2.0×10^−6 s. Let's use these values to find I.

$\begin{gathered} I=\frac{2.0\times10^{-4}C}{2.0\times10^{-6}\sec } \\ I=1.0\times10^{-4-(-6)}A \\ I=1.0\times10^{-4+6}A \\ I=1.0\times10^2A \end{gathered}$

<em>As you can observe above, the division of the powers was solved by just subtracting their exponents.</em>

<em />

<h2>Therefore, the rate of the current flow is 1.0×10^2 A.</h2>

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1 year ago

Three monkeys A, B, and C weighing 20, 26, and 25 lb, respectively, are climbing up and down the rope suspended from D. At the i

Marina86 [1]

Answer: $2235.2lb-ft/s^2$

Explanation:

Given

Mass of monkey A=20lb

Mass of monkey B=26lb

Mass of monkey C=25lb

acceleration of monkey A= $4.2ft/s^2$

acceleration of monkey B=0

acceleration of monkey C= $-5.4ft/s^2$

Force Due to monkey A $\left ( F_A\right )=20\times 4.2 =84lb-ft/s^2\left ( downwards\right )$

Force Due to monkey A $\left ( F_B\right )=26\times 0 =0lb-ft/s^2$

Force Due to monkey A $\left ( F_C\right )=25\times 5.4 =135 lb-ft/s^2\left ( upward\right )$

In addition to it Weights of monkeys will be acting downwards therefore net Downwards force is balanced by tension

T= $\left ( 20+26+25\right )32.2+84-135=2235.2 lb-ft/s^2$

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3 years ago

In 1947 Thor Heyerdahl sailed a simple raft from Peru to Polynesia, following the ocean currents for more than 6,000 kilometers.

GenaCL600 [577]

The correct answer of the given question above would be option C. In 1947 Thor Heyerdahl sailed a simple raft from Peru to Polynesia, following the ocean currents for more than 6,000 kilometers.<span> This statement accurately describes what Heyerdahl proved by this voyage. It would have been possible for people from ancient Peru to reach Polynesia by following ocean currents. </span>

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3 years ago

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