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Dmitry_Shevchenko [17]
3 years ago
15

A golfer strikes a 0.059-kg golf ball with a force of 290 N. If the ball moves with a velocity of 69 m/s,

Physics
1 answer:
Ymorist [56]3 years ago
4 0

Answer:

0.014s

Explanation:

Given parameters:

mass of golf ball  = 0.059kg

force applied  = 290N

velocity = 69m/s

initial velocity  = 0m/s

Unknown:

Time of contact  = ?

Solution;

We know that momentum is the quantity of motion of body possess;

  Momentum  = mass x velocity

  Momentum  = 0.059 x 69  = 4.1kgm/s

Also; impulse is the effect of the force acting on a body;

  impulse  = force x time  = momentum

  So;

            Force x time  = momentum

                  Time  = \frac{momentum}{force }    = \frac{4.1}{290}    = 0.014s

 

 

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A 200-turn flat coil of wire 30.0 cm in diameter acts as an antenna for FM radio at a frequency of 100 MHz. The magnetic field o
dalvyx [7]

Answer:

a) 8.4×10^-12W

b) 5.65 ×10^ -3V

c) 1.01 ×10^ -12 F

Explanation: Given:

Radius r = d/2 = 30/2=15cm= 0.15m

Maximum feild strength = Bo= 10^-12 T

Permiability of vacuum, Uo = 4pi×10^-7

I = CBo/2Uo = (3 ×10^8×(10^-12)^2)/ (4 ×3.142×10^-7)

I = 1.19×10^-10W/m^2

The intensity I = > P/A = p = IA = I(4pi^2)

P = 1.19×10^-10 × 3.142 × (0.15^2)

P = 8.4 × 10^-12W

b) Given: f = 100Mhz= 100×10^6hz

Number of turns in the coil, N = 200

Time of cycle, T = 1/f = 1/ 100×10^6

T = 10^-8 seconds

Change in t= 1/4T = 1/4×10^-8 = 2.5 ×10^-9sec

E = (N×change in B×A)/ change in t

E = (NBopir^2)/change in t

E = (200 ×10^-12× 3.142 ×(0.15^2))/ (2.5×10^-9)

E = 5.65 ×10^-3V

c) Self inductance L = 2.5UH=2.5×10^-6H

Resonant frequency, fo= 1/(2pisqrt(LC))

C= 1/(4×3.142×( 2.5×10^-6)× (100×10^6)^2

C = 1.01×10^-12F

3 0
4 years ago
Read 2 more answers
A test of the prototype of a new automobile shows that the minimum distance for a controlled stop from 95 km/h to zero is 55 m.
iris [78.8K]

Answer:

-0.64525g

Explanation:

t = Time taken for the car to stop

u = Initial velocity = 95 km/h

v = Final velocity = 0 km/h

s = Displacement

a = Acceleration

Equation of motion

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-95^2}{2\times 0.055}\\\Rightarrow a=-82045.45\ km/h^2

Converting to m/s²

a=82045.45=\frac{82045.45\times 1000}{3600\times 3600}=-6.33\ m/s^2

g = Acceleration due to gravity = 9.81 m/s²

Dividing both the accelerations, we get

\frac{a}{g}=\frac{-6.33}{9.81}=-0.64525\\\Rightarrow a=-0.64525g

Hence, acceleration of the car is -0.64525g

8 0
4 years ago
sandra lives in a country located in the northern hemisphere she makes a sundial by erecting a pole vertically in her garden the
Arte-miy333 [17]

Answer:

C

Explanation:

The sun has rotated causing the shadow to reflect.

5 0
3 years ago
Where would you most likely find regional metamorphism? associated with a mountain belt associated with a volcano associated wit
vladimir1956 [14]
Regional metamorphism is a type of metamorphism in which the minerals and the textures of the rocks are changed or altered due to the effect of pressure and heat over a wide area or region.
This type of metamorphism often results in metamorphic rocks that are strongly foliated.
Metamorphism usually occurs in the folds of thrust mountain belts.

Answer: You would most likely find regional metamorphism associated with a mountain belt.

5 0
3 years ago
Read 2 more answers
Two small insulating spheres with radius 3.50×10−2 m are separated by a large center-to-center distance of 0.555 m. One sphere i
xz_007 [3.2K]

Answer:

E = 7.83 \times 10^5 N/C

Explanation:

Since we know that two sphere is oppositely charged so net electric field at the mid point of two balls will be sum of the electric field due to each ball at the mid point

So we know that

E = \frac{kq_1}{r^2} + \frac{kq_2}{r^2}

here we know that

q_1 = 4.20 \mu C

q_2 = 2.50 \mu C

r = \frac{0.555}{2}

so we have

E = \frac{(9\times 10^9)(4.20 + 2.50) \times 10^{-6}}{0.2775^2}

E = 7.83 \times 10^5 N/C

4 0
3 years ago
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