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Dmitry_Shevchenko [17]
3 years ago
15

A golfer strikes a 0.059-kg golf ball with a force of 290 N. If the ball moves with a velocity of 69 m/s,

Physics
1 answer:
Ymorist [56]3 years ago
4 0

Answer:

0.014s

Explanation:

Given parameters:

mass of golf ball  = 0.059kg

force applied  = 290N

velocity = 69m/s

initial velocity  = 0m/s

Unknown:

Time of contact  = ?

Solution;

We know that momentum is the quantity of motion of body possess;

  Momentum  = mass x velocity

  Momentum  = 0.059 x 69  = 4.1kgm/s

Also; impulse is the effect of the force acting on a body;

  impulse  = force x time  = momentum

  So;

            Force x time  = momentum

                  Time  = \frac{momentum}{force }    = \frac{4.1}{290}    = 0.014s

 

 

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Answer:

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Answer:

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Explanation:

It is given that,

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Let n is the number of excess electrons are on that plate. Using the quantization of charges, the total charge on the negative plate is given by :

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