Question

Calculate the kinetic energy of a 8.8 x 10^13 kg comet moving at a speed of 33.0 km/s. Round your answer to 2 significant digits?

Answer 1

Answer:

$KE=4.79\times 10^{22}\ J$

Explanation:

Given that

Mass ,m= 8.8 x 10¹³

Speed ,v= 33 km/s

We know that 1 km= 1000 m

v= 33 x 10³ m/s

As we know that kinetic energy given as

$KE=\dfrac{1}{2}mv^2$

Now by putting the values in the above equation

$KE=\dfrac{1}{2}\times 8.8\times 10^{13}\times 33000^2$

$KE=4.7916\times 10^{22}\ J$

Therefore we can say that the kinetic energy will be

$KE=4.79\times 10^{22}\ J$