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Vikki [24]
3 years ago
6

What is the least number of peptides in a polypeptide? 10 50

Chemistry
2 answers:
Vladimir [108]3 years ago
8 0
The answer is 10 ……………………..
kirill115 [55]3 years ago
4 0

Answer : The least number of amino acids in a polypeptide are 10

Explanation :

A peptide is a compound which is formed by joining of 2 or more amino acids by peptide linkage.

Depending on the number of amino acids involved in the formation of the peptide,it can be classified as follows.

1) Dipeptide : This is the shortest peptide chain and contains only 2 amino acids.

2) Polypeptide : This is formed when 10 or more amino acids are joined together. A polypeptide can have 10 to 50 amino acid molecules.

When the number of amino acids are more than 50, then the compound is termed as a "protein".

Therefore we can say that the least number of amino acids in a polypeptide are 10.

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A new Material is formed.

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For the equilibrium PCl5(g) PCl3(g) + Cl2(g), Kc = 2.0 × 101 at 240°C. If pure PCl5 is placed in a 1.00-L container and allowed
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Answer:

the equilibrium concentration of [PCl₅] is 3.64*10⁻³ M

Explanation:

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Kc= [PCl₃]*[Cl₂]/[PCl₅] = 2.0*10¹ M = 20 M

and [A] denote concentrations of A

if initially the mixture is pure PCl₅ , then it will dissociate according to the reaction and since always one mole of PCl₃(g) is generated with one mole of Cl₂(g) , the total number of moles of both at the end is the same → they have the same concentration → [PCl₃(g)] = [Cl₂]=0.27 M

therefore

Kc= [PCl₃]*[Cl₂]/[PCl₅] = 0.27 M* 0.27 M /[PCl₅] = 20 M

[PCl₅]  =  0.27 M* 0.27 M / 20 M = 3.64*10⁻³ M

[PCl₅]  = 3.64*10⁻³ M

the equilibrium concentration of [PCl₅] is 3.64*10⁻³ M

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