Answer:
0.425 L
Explanation:
Given the information from the question. We know that the water heat evaporation is given by 2261 KJ/kg. Therefore, for each Kg of vapor, 2261 is required.
To calculate the amount of water evaporated by 960 KJ is as follows
= (1/2260)*960 =0.425 Kg
In other words, 0.425 of water is evaporated by 960 KJ.
To calculate the volume of water, we have mass and density. Therefore, Volume = Mass/Density = 425g/1g/ml = 0.425 L.
Therefore, water evaporated is 0.425 L
Answer:
Covalent network solids are formed by networks or chains of atoms or molecules held together by covalent bonds. Consists of sp3 hybridized carbon atoms, each bonded to four other carbon atoms in a tetrahedral array to create a giant network. Examples of network covalent solids include diamond and graphite (both allotropes of carbon), and the chemical compounds silicon carbide and boron-carbide.
Answer: 63.88 atm
Explanation:
To answer this, we use the formula PV = nRT since the asumption is that the gas has an ideal behavior
where number of mole = 2.60 mol, R(gas constant) = 0.08205746 L atm/K mol,
T = 251 ∘C = (251 + 273) K = 524 K, Volume = 1.75 L
Making Pressure the subject of the formula, we have
P = nRT/V = 2.6 * 0.08205746 * 524/2.75 = 63.88 atm
Answer:
The atoms are vibrating in place.
Explanation:
One of the properties of an ionic substance is the possession of a crystalline structure. As Gerry observed the salt under a microscope, he discovered that it has a crystalline structure. Crystalline salts are all ionic in nature, hence the salt observed by Gerry is an ionic salt.
Solids containing a definite crystalline structure always has their particles vibrating in place. This is immediately evident as Gerry looks at the salt through a microscope.
A 0.25m solution of NaCl is defined as a solution consisting of 0.25mol NaCl dissolved in 1kg water:
Which choice fits this definition: None does. I suggest that you recheck the data you have submitted - you have a mixture of moles, mass, etc and it is easy to make a mistake.
d) looks promising if it was: 1.0 mol NaCl dissolved in 4kg water.
I have overlooked C) as possible 0.25mol NaCl in 1kg water as being a little too obvious.
