<h3>
Answer:</h3>
P₂ = 0.67 atm
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Chemistry</u>
<u>Gas Laws</u>
Boyle's Law: P₁V₁ = P₂V₂
- P₁ is pressure 1
- V₁ is volume 1
- P₂ is pressure 2
- V₂ is volume 2
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] P₁ = 2.02 atm
[Given] V₁ = 4.0 L
[Given] V₂ = 12.0 L
[Solve] P₂
<u>Step 2: Solve</u>
- Substitute in variables [Boyle's Law]: (2.02 atm)(4.0 L) = P₂(12.0 L)
- [Pressure] Multiply: 8.08 atm · L = P₂(12.0 L)
- [Pressure] [Division Property of Equality] Isolate unknown: 0.673333 atm = P₂
- [Pressure] Rewrite: P₂ = 0.673333 atm
<u>Step 3: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs as our smallest.</em>
0.673333 atm ≈ 0.67 atm
You can measure length wiht the greatest preciaion using a tape measure marked in milimeters.
Answer: C. milimeters.
Answer:
0.481 M
Explanation:
The molarity ratio looks like this:
Molarity = moles / volume (L)
Since you have been given both the mass and volume, you can plug them into the equation to find the molarity.
Molarity = moles / volume
Molarity = 0.650 moles / 1.35 L
Molarity = 0.481 M
initial condition : Vi = 4.700 L , Ti = 71.0ºC +273 => 344 K
final condition : Vf = 3.300 L , Tf = ?
Pressure is constant:
According to charle's law , volume is directly proportional to temperature at constant pressure !
Hence Vi / Ti = Vf / Tf
4.700 L / 344 K = 3.300 L / Tf
Tf = 3.300 L * 344 K / 4.700 L
Tf = 1135200 / 4.700
Tf = 241.53 K
Tf = 241.53 - 273
Tf = -31.47ºC