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2 years ago

Please help me in so confused

Mathematics

1 answer:

jolli1 [7]2 years ago

5 0

Answer:

Step-by-step explanation:

Similar figures have sides in the same ratio

169/1.3 = 17/x

x = 17×1.3/169

x = 0.131 m

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meriva

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3 years ago

Two skaters are practicing at the same time on the same rink. A coordinate grid is superimposed on the ice. One skater follows t

myrzilka [38]

Answer:

The skaters will collide at the points;

(2,28) and (4,24)

Step-by-step explanation:

The points they might collide will be the points when both y are equal;

-2x + 32 = -2x^2 + 18x

2x^2 -18x -2x + 32 = 0

2x^2 -20x + 32 = 0

2x^2 - 16x - 4x + 32 = 0

2x(x -8) -4( x -8) = 0

(2x -4)(x -8) = 0

2x = 4 or x = 8

x = 4/2 or x = 8

hence; x = 2 or 8

Now let’s get the y value

at x = 2, just substitute into any of the 2

y = -2x + 32

y = -2(2) + 32

y = -4 + 32 = 28

at x = 4

y = -2(4) + 32

y = -8 + 32

y = 24

The points that they will collide are;

(2,28) and (4,24)

4 0

3 years ago

The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

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3 years ago

Read 2 more answers

2 meters<br> 2 meters<br> 5 meters<br> 4 meters<br> What is the area of the shape?

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3 years ago

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HELP PLEASE!! WILL GIVE BRAINLIEST TO CORRECT QNSWER.

asambeis [7]

X = 1/2 =0.500

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2 years ago