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Inessa [10]
3 years ago
8

Please help me in so confused

Mathematics
1 answer:
jolli1 [7]3 years ago
5 0

Answer:

A

Step-by-step explanation:

Similar figures have sides in the same ratio

169/1.3 = 17/x

x = 17×1.3/169

x = 0.131 m

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The ratio of students that ride the bus as compared to those that walk on 10:1. Does this school have more students that ride th
NeTakaya

Answer: Yes they do.


Step-by-step explanation:

This because the ratio 10:1 means that for every 10 students that ride the bus only one walks. So if you had 30 students riding he bus you would only have 3 students that walked. So no matter what you will have more kids riding the bus.

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3 years ago
Find the coordinates of the image of point R(5, –4) rotated 90 degrees about the origin.
Nat2105 [25]
(-4,-5) would be the answer
7 0
4 years ago
Steve buys 2 lb of grapefruit and 3 lb of oranges for $7.20. Kennedy buys 4 lb of grapefruit and 2 lb of oranges for $8.80. Let
MrMuchimi

Answer: \left \{ {{2x+3y=7.20} \atop {4x+2y=8.80}} \right.

Step-by-step explanation:

Let be "x"  the price per pound for grapefruit, "y" the price per pound for oranges.

We know that Steve buys 2 pounds of grapefruit and 3  of oranges for $7.20.

This means that the sum of the products of 2x and 3y is $7.20. Then, we can write this equation to represent it:

2x+3y=7.20

Kennedy buys 4 pounds of grapefruit and 2 pounds of oranges for $8.80.

This means that the sum of the products of 4x and 2y is $8.80. Then, we can write this equation to represent this:

4x+2y=8.80

Therefore, we get that the system of equations that models the situation is:

\left \{ {{2x+3y=7.20} \atop {4x+2y=8.80}} \right.

8 0
3 years ago
Y+3/5<br><img src="https://tex.z-dn.net/?f=%20%5Cgeqslant%20" id="TexFormula1" title=" \geqslant " alt=" \geqslant " align="absm
kodGreya [7K]
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3 0
3 years ago
Shelia's measured glucose level one hour after a sugary drink varies according to the normal distribution with μ = 132 mg/dL and
Lelechka [254]

Answer:

134.6

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula. This is X when Z has a p-value of 1-0.01 = 0.99. So it is X when Z = 2.325.

The level is L = 134.6

The Central Limit Theorem estabilishes that, for a random variable X, with mean  and standard deviation, large sample size can be approximated to a normal distribution with a mean and standard deviation

8 0
3 years ago
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