Answer:
12 J
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 7.6 kg
Distance (d) = 6 m
Velocity (v) = 5 m/s
Force (F) = 2 N
Workdone (Wd) =.?
Workdone can be defined as the product of force and distance moved in the direction of the force. Mathematically, it is expressed as:
Workdone = Force × distance
Wd = F × d
With the above formula, we can obtain the workdone as follow:
Distance (d) = 6 m
Force (F) = 2 N
Workdone (Wd) =.?
Wd = F × d
Wd = 2 × 6
Wd = 12 J
Thus, the workdone is 12 J
Answer:
v = 3.27 m/s
Explanation:
KE = 1/2 mv^2
695 J = 1/2 (130kg)(v^2)
695 J / (1/2 x 130kg) = v^2
v^2 = square root of 10.69
v = 3.27 m/s
It’s going 3m/s. If we have 5 seconds to work with then we can find the acceleration by adding speed and how fast it going every second. So like the 7-10-13-16-19 so we go 3m/s faster ever second