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Ray Of Light [21]
3 years ago
14

What allows a pump to raise fluids in pipes

Physics
1 answer:
erastova [34]3 years ago
8 0

Answer: The energy to move the fluid is provided by the pressure on the fluid surface.

Explanation:  The frictional losses in the suction pipework and rises in the suction pipework system will reduce the fluid pressure at the pump inlet. If the pump inlet connection is removed the fluid will not flow out of the suction pipework. Hope this helps! :)

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Please show work with the answer and thank you
Alika [10]

Answer:

its your homework

Explanation:

you aren't getting any free answers out of me because it sounds like your trying to be smart your welcome

(Not smarter than me)

7 0
3 years ago
How much heat is required to convert 0.3 kilogram of ice at 0°C to water at the same temperature
Grace [21]

Answer:

100,200J of heat is required to convert 0.3kg of ice of 0°C to water at same temperature.

Explanation:

Heat = mass * lf

Latent heat of fusion (lf) of water is 334J/g

Heat = 300g * 334 J/g

Heat = 100,200J of heat

6 0
3 years ago
Read 2 more answers
A 10 Newton effort force is required to lift a 10 kg box just off the ground. What is the effort required to lift the box off th
Karo-lina-s [1.5K]

2.0 N is the answer, I hope this helps :D




5 0
3 years ago
Read 2 more answers
Find the voltage change when: a. An electric field does 12 J of work on a 0.0001-C charge. b. The same electric field does 24 J
kondaur [170]

Explanation:

Given that,

(a) Work done by the electric field is 12 J on a 0.0001 C of charge. The electric potential is defined as the work done per unit charged particles. It is given by :

V=\dfrac{W}{q}

V=\dfrac{12}{0.0001}

V=12\times 10^4\ Volt

(b) Similarly, same electric field does 24 J of work on a 0.0002-C charge. The electric potential difference is given by :

V=\dfrac{W}{q}

V=\dfrac{24}{0.0002}

V=12\times 10^4\ Volt

Therefore, this is the required solution.

7 0
3 years ago
A snowball with a mass of 85 g hits the top hat of a 1.5 m tall snowman and sticks to it. the hat and the snowball, with a combi
LenaWriter [7]
Part (a): Velocity of the snowball
By conservation of momentu;
m1v1 + m2v2 = m3v3,

Where, m1 = mass of snowball, v1, velocity of snowball, m2 = mass of the hat, v2 = velocity of the hat, m3 = mass of snowball and the hat, v3 = velocity of snowball and the hut.

v2 = 0, and therefore,
85*v1 + 0 = 220*8 => v1 = 220*8/85 = 20.71 m/s

Part (b): Horizontal range
x = v3*t
But,
y = vy -1/2gt^2, but y = -1.5 m (moving down), vy =0 (no vertical velocity), g = 9.81 m/s^2

Substituting;
-1.5 = 0 - 1/2*9.81*t^2
1.5 = 4.905*t^2
t = Sqrt (1.5/4.905) = 0.553 seconds

Then,
x = 8*0.553 = 4.424 m
7 0
3 years ago
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