Answer:
The three laws of motion were first compiled by Isaac Newton in his Philosophiæ Naturalis Principia Mathematica (Mathematical Principles of Natural Philosophy), first published in 1687. Newton used them to explain and investigate the motion of many physical objects and systems
Answer:
It is a change in velocity over a period of time.
Explanation:
- It is measured in metres/second2<em><u> </u></em><em><u>u</u></em><em><u>s</u></em><em><u>i</u></em><em><u>n</u></em><em><u>g</u></em><em><u> </u></em><em><u>a</u></em><em><u>n</u></em><em><u> </u></em><em><u> </u></em><em><u>accelerometer</u></em><em><u>.</u></em>
The cell belongs to the then musculoskeletal system of the body.
<h3>What type of cells contains filaments that can cause the cell to contract, shortening the length of the cell?</h3>
The myocytes or muscle cells are special cells found in smooth, cardiac, and skeletal muscles that have differentiated for the specialized function of contraction.
Myocytes are long, cylindrical, multi-nucleated, and striated. They contain filaments that can cause the cell to contract, shortening the length of the cell.
Skeletal muscle cells contain many mitochondria required to generate sufficient ATP since skeletal muscle cells have high energy requirements.
The muscle cells form a part of the musculoskeletal system of the body.
In conclusion, muscle cells are required for muscular contraction.
Learn more about muscle cells at: brainly.com/question/15441674
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Answer:
a) 90 kJ
b) 230.26 kJ
Explanation:
The pressure at the first point = 10 bar —> 10 x 102 = 1020 kPa
The volume at the first point = 0.1 m^3
The pressure at the second point = 1 bar —> 1 x 102 = 102 kPa
The volume at the second point = 1 m^3
Process A.
constant volume V = C from point (1) to P = 10 bar.
Constant pressure P = C to the point (2).
Process B.
The relation of the process is PV = C
Required
For process A & B
(a) Sketch the process on P-V coordinates
(b) Evaluate the work W in kJ.
Assumption
Quasi-equilibrium process
Kinetic and potential effect can be ignored.
Solution
For process A.
V=C
There is no change in volume then
The work is defined by
║ V║limit 1--0.1
90 kJ
Process B
PV=C
By substituting with point (1) C = 10^2 x 1= 10^2
The work is defined by
║ ln(V)║limit 1--0.1
=230.26 kJ
i. 1,350 calories
j. 992 calories
k. 235.6 calories
2. Calories of energy into water = (amount of water, in grams) x (change in the water's temperature, in °C)
3.a. 840 calories
3.b. 840 calories
4. 80°C