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4 years ago

Using your own words, tell me

2 answers:

6 0

a pure substance is a substance that has not been mixed with anything, a mixture has been mixed with another substance. an example is

dirt +water=mud iron is an example of a substance

Leokris [45]4 years ago

4 0

Answer:

Hey there!

Mixtures are physically combined and can be separated. For example, sand and water is a mixture.

Pure substances are samples of matter with definite, and unchangeable chemical properties. For example, diamond is a pure substance.

Let me know if this helps :)

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Rcise 5

DochEvi [55]

The acceleration of the train at the give initial and final velocity is determined as 10.5 m/s².

<h3>Acceleration of the train</h3>

The acceleration of the train is calculated as follows;

a = Δv/t

where;

u is initial velocity = 162 km/hr = 45 m/s
v is final velocity of the car = 540 km/hr = 150 m/s

a = (150 - 45)/10

a = 10.5 m/s²

Thus, the acceleration of the train at the give initial and final velocity is determined as 10.5 m/s².

Learn more about acceleration here: brainly.com/question/605631

#SPJ1

5 0

2 years ago

Use the values from PRACTICE IT to help you work this exercise. Suppose the same two vehicles are both traveling eastward, the c

Mariulka [41]

Answer:

A. $v_{3}=12.17m/s$

B. $v_{car}=6.3m/s\\v_{truck}=-6.3m/s$

C. ΔK $=-4.13x10^3J$

Explanation:

From the exercise we know that the car and the truck are traveling eastward. I'm going to name the car 1 and the truck 2

$v_{1}=5.79m/s\\m_{1}=102kg\\v_{2}=18.5m/s\\m_{2}=103kg$

A. Since the two vehicles become entangled the final mass is:

$m_{3}=102kg+103kg=205kg$

From linear momentum we got that:

$p_{1}=p_{2}$

$m_{1}v_{1}+m_{2}v_{2}=m_{3}v_{3}$

$v_{3}=\frac{m_{1}v_{1}+m_{2}v_{2}}{m_{3} }=\frac{(102kg)(5.79m/s)+(103kg)(18.5m/s)}{(205kg)}$

$v_{3}=12.17m/s$

B. The change in velocity of both vehicles are:

For the car

$v_{car}=v_{f}-v_{o}=12.17m/s-5.79m/s=6.38m/s$

For the truck

$v_{truck}=12.17m/s-18.5m/s=-6.3m/s$

C. The change in kinetic energy is:

ΔK= $K_{2}-K_{1} =\frac{1}{2}m_{3}v_{3}^{2}-(\frac{1}{2}m_{1}v_{1}^{2}+\frac{1}{2}m_{2}v_{2}^{2})$

ΔK= $\frac{1}{2}(205)(12.17)^{2}-(\frac{1}{2}(102)(5.79)^{2}+\frac{1}{2}(103)(18.5)^{2})=-4.13x10^{3}J$

ΔK $=-4.13x10^{3}J$

6 0

4 years ago

a scale model of the solar system where 50 cm represents 1.0x10 to the fifth km is actual distance what would be the dimension o

Fofino [41]

The distance between Mars and the Sun in the scale model would be 1140 m

Explanation:

In this scale model, we have:

$x_1 = 50 cm$ represents an actual distance of

$d_1 = 1.0\cdot 10^5 km$

The actual distance between Mars and the Sun is 228 million km, therefore

$d_2=228\cdot 10^6 km$

On the scale model, this would corresponds to a distance of $x_2$ .

Therefore, we can write the following proportion:

$\frac{x_1}{d_1}=\frac{x_2}{d_2}$

And solving for $x_2$ , we find:

$x_2=\frac{x_1 d_2}{d_1}=\frac{(50)(228\cdot 10^6)}{1\cdot 10^5}=1.14\cdot 10^5 cm = 1140 m$

Learn more about distance:

brainly.com/question/3969582

#LearnwithBrainly

4 0

3 years ago

A 12 A fuse is placed in a parallel circuit that has two branches. 8 A flows in branch 1 and 6 A flows in branch 2. This fuse

kaheart [24]

Answer:

1. will blow because the total current in this circuit is 14 A which is greater than 12 A.

Explanation:

According to Kirchoff current law (KCL) which states that the total current flowing in a circuit is equal to the sum of the individual branch current.

If the supply current is greater than the sum of the individual branch current, then the load will collapse or blow off.

In the question given, the total current of the fuse is 12A

Sum of branch currents = current in branch 1 + current in branch 2

= 8A+6A

= 14A

As we can see that the supply current is lower than the sum of the branch current, this will cause the fuse to blow because some of the branch current will be sent back on the fuse and thereby causing the fuse to blow.

3 0

4 years ago

A thin, uniform rod is hinged at its midpoint. to begin with, one-half of the rod is bent upward and is perpendicular to the oth

elena-14-01-66 [18.8K]

<span>Answer: initial I = (m/2)LÂ˛/3 + (m/2)LÂ˛ where L = Â˝ the length of the rod, and the vertical half can be treated as a point mass. initial I = mLÂ˛(1/6 + 1/2) = 2mLÂ˛/3 final I = m(2L)Â˛/3 = 4mLÂ˛/3 Since I has doubled and momentum is conserved, Ď‰ has halved. Ď‰ = 3.9 rad/s. By formulae: 2mLÂ˛/3 * 7.8rad/s = 4mLÂ˛/3 * Ď‰</span>

5 0

4 years ago

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