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svetlana [45]
3 years ago
8

The 225-N force is exerted on the crate towards the north and the 165-N is exerted toward the East what's the magnitude and dire

ction of the net force
Physics
1 answer:
Rudik [331]3 years ago
6 0

Answer:

≅279.02 N, 36° 15' from North to East

Explanation:

You can the theory of triangle of forces to find the answer.

Two forces are acting perpendicular to each other so use Pythagoras theorem to find the magnitude of the resultant  force(x).

x² = 225² + 165²

x = 279.02 N

To find the direction use the same force triangle,

Workings are in the attachment,

Download pdf
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A plane accelerates from 25 m/s to a velocity of 80 m/s in a time of 5 seconds. What
Natali [406]

Answer:

-7

Explanation:

-7 because -7 said so

6 0
3 years ago
Ann (mass 50 kg) is standing at the left end of a 15-m-long, 500 kg cart that has frictionless wheels and rolls on a frictionles
ivanzaharov [21]

Answer:

13.5 m

Explanation:

M = Mass of cart = 500 kg

m = Ann's mass = 50 kg

v_m = Velocity of Ann relative to cart = 5 m/s

v_M = Velocity of Cart relative to Ann

As the linear momentum of the system is conserved

Mv_M+mv_m=0\\\Rightarrow v_M=-\frac{mv_m}{M}\\\Rightarrow v_M=-\frac{50\times 5}{500}\\\Rightarrow v_M=-0.5\ m/s

Time taken to reach the right end by Ann

Time=\frac{Distance}{Speed}\\\Rightarrow Time=\frac{15}{5}=3\ s

Distance the cart will move in the 3 seconds

Distance=Speed\times Time\\\Rightarrow Distance=-0.5\times 3=-1.5\ m

The negative sign indicates opposite direction

Movement of Ann will be the sum of the distances

15+(-1.5)=13.5\ m

The net movement of Ann is 13.5 m

5 0
2 years ago
List the names of two tectonic plates that are NOT part of the ring of fire
Ann [662]
Nolur acil lütfen yalvarırım yalvarırım
5 0
2 years ago
An arrow is launched from a bow with an initial horizontal velocity of 40
Ivan

Answer:

V = (Vx^2 + Vy^2)^1/2 = (40^2 + 62^2)^1/2

V = 73.8 m/s

tan theta = Vy / Vx = 62/40 = 1.55

theta = 57.2 deg

4 0
2 years ago
The capacitor is now disconnected from the battery, and the plates of the capacitor are then slowly pulled apart until the separ
alexdok [17]

Answer:

U₁ = (ϵAV²)/6d

This means that the new energy of the capacitor is (1/3) of the initial energy before the increased separation.

Explanation:

The energy stored in a capacitor is given by (1/2) (CV²)

Energy in the capacitor initially

U = CV²/2

V = voltage across the plates of the capacitor

C = capacitance of the capacitor

But the capacitance of a capacitor depends on the geometry of the capacitor is given by

C = ϵA/d

ϵ = Absolute permissivity of the dielectric material

A = Cross sectional Area of the capacitor

d = separation between the capacitor

So,

U = CV²/2

Substituting for C

U = ϵAV²/2d

Now, for U₁, the new distance between plates, d₁ = 3d

U₁ = ϵAV²/2d₁

U₁ = ϵAV²/(2(3d))

U₁ = (ϵAV²)/6d

This means that the new energy of the capacitor is (1/3) of the initial energy before the increased separation.

3 0
2 years ago
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