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3 years ago

What are some non-examples of subatomic particles

1 answer:

7 0

Subatomic particles are smaller than an atom. Therefor, anything made of atoms is not subatomic. Examples of non subatomic particles are molecules and compounds.

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Determine the oxidation number for nitrogenin

iris [78.8K]

Answer:

1(a) N = 3

(b) N = 0

(d) N = -2

(2) Molecular formula for benzene is C6H6

Explanation:

1(a) N02 1-

N + (2×-2) = -1

N-4 = -1

N = -1+4 = 3

(b) N2

2(N) = 0

N = 0/2 = 0

N + ( 2×-2) + (-1) = 0

N - 4 - 1 = 0

N - 5 = 0

N = 0+5 = 5

(d) N2H4

2(N) + (4×1) = 0

2N + 4 = 0

2N = 0 - 4 = -4

N = -4/2 = -2

(2) Molcular mass of benzene = 78g/mole = (6×12g of carbon) + (6×1g of hydrogen) = 72+6 = 78g/mole

Therefore, molecular formula for benzene is C6H6

7 0

4 years ago

9. Sodium reacts with water to produce sodium hydroxide and hydrogen gas, as shown below.

saveliy_v [14]

Answer:

Explanation:

2Na + 2H2O2==NaOh + H2

184/23=x/18

x=(184×18)/23

x=144g

4 0

3 years ago

Which process will decrease the level of CO2 in the atmosphere?

Pie

I believe that A is the answer. :)

8 0

3 years ago

One gram-mole of methyl chloride vapor is contained in a vessel at 100°C and 10atm.(a) Use the ideal-gas equation of state to es

777dan777 [17]

Answer:

a) The volume of the system is 3.062 Liters.

b) Percentage error results from assuming ideal-gas behavior is 9.36%.

Explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas = $10 atm$

V = Volume of gas = ?

n = number of moles of gas = 1 mol

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 100°C = 100+273K=373 K

Putting values in above equation, we get:

$(10 atm)\times V=1 mol\times (0.0821L.atm/mol.K)\times 373 K$

$V=\frac{1 mol\times (0.0821L.atm/mol.K)\times 373 K}{10 atm}$

V = 3.062 L

The volume of the system is 3.062 Liters.

Volume of the container = V' = 2.8 L

System volume = V = 3.062 L

Percentage error of volume:

To calculate the percentage error, we use the equation:

$\%\text{ error}=\frac{|\text{Experimental value - Accepted value}|}{\text{Accepted value}}\times 100$

$=\frac{|3.062L-2.8 L|}{2.8 L}\times 100=9.36\%$

Percentage error results from assuming ideal-gas behavior is 9.36%.

6 0

3 years ago

The image below represents which of the following (Check all that apply):

mihalych1998 [28]

What was he answer?? Please I am taking the test, what are they.

6 0

3 years ago

Read 2 more answers