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a_sh-v [17]
3 years ago
11

A reaction is followed and found to have a rate constant of 3.36 × 104 M-1s-1 at 344 K and a rate constant of 7.69 M-1s-1 at 219

K. Determine the activation energy for this reaction.23.8 kJ/mol11.5 kJ/mol12.5 kJ/mol42.0 kJ/mol58.2 kJ/mol
Chemistry
1 answer:
Mashutka [201]3 years ago
8 0

Answer:

Ea = 42,0 kJ/mol

Explanation:

It is possible to solve this question using Arrhenius formula:

ln\frac{k2}{k1} = \frac{-Ea}{R} (\frac{1}{T2} -\frac{1}{T1} )

Where:

k1: 3,36x10⁴ M⁻¹ s⁻¹

T1: 344K

Ea = ???

R = 8,314472x10⁻³ kJ/molK

k2 : 7,69 M ⁻¹ s⁻¹

T2: 219K

Solving:

-8,382 = \frac{-Ea}{8,314472x10^{-3}kJ/molK} (1,659x10^{-3}K^{-1})

-8,382 = -Ea*0,19956mol/kJ

-8,382 = -Ea*0,19956mol/kJ

-42,0 kJ/mol = -Ea

<em>Ea = 42,0 kJ/mol</em>

<em></em>

I hope it helps!

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Answer:

According to Le Chatelier's principle, increasing the reaction temperature of an exothermic reaction causes a shift to the left and decreasing the reaction temperature causes a shift to the right.

Explanation:

C6H12O6(s) + 6O2(g) ⇌6CO2(g) + 6H2O(g)

We are told that the forward reaction is exothermic, meaning heat is removed from the reacting substance to the surroundings.

According to Le Chatelier's principle,

1. for an exothermic reaction, on increasing the temperature, there is a shift in equilibrium to the left and formation of the product is favoured.

2. if the temperature of the system is decreased, the equilibrium shifts to right and the formation of the reactants is favoured.

3. if the reaction temperature is kept constant, the system is at equilibrium and there is no shift to the right nor to the left.

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3 years ago
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Answer:

D.

Explanation:

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In this case, the isomer of an organic compound is another organic compound having the same molecular formula but different structural formula, thus, the given compound's molecular formula is C₅H₈ since it is an alkyne due to the triple bond. Next, we analyze each option:

A. C₅H₁₂

B. C₅H₁₀

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For that reason answer is D. based on the molecular formula as well as due to the presence of the triple bond unsaturation (alkyne as well).

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Suppose you have a sample of table salt (NaCl) that has a mass of 100.0 grams. If
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Taking into account the definition of molarity, the concentration of the solution is 0.855 \frac{moles}{liter}.

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

Molarity=\frac{number of moles}{volume}

Molarity is expressed in units \frac{moles}{liter}.

<h3>Molarity of NaCl</h3>

In this case, you have:

  • number of moles of NaCl= 100 grams\frac{1 mole}{58.45 grams} =1.71 moles (being 58.45 g/mole the molar mass of NaCl)
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Replacing in the definition of molarity:

Molarity=\frac{1.71 moles}{2 L}

Solving:

Molarity= 0.855 \frac{moles}{liter}

Finally, the concentration of the solution is 0.855 \frac{moles}{liter}.

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