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3 years ago

Name careers that find cures for diseases

Chemistry

2 answers:

brilliants [131]3 years ago

8 0

Medical device the company Gore where my mom works

Y_Kistochka [10]3 years ago

6 0

Any type of medical scientist works.

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A 0.25-mol sample of a weak acid with an unknown Pka was combined with 10.0-mL of 3.00 M KOH, and the resulting solution was dil

Masteriza [31]

Answer : The value of $pK_a$ of the weak acid is, 4.72

Explanation :

First we have to calculate the moles of KOH.

$\text{Moles of }KOH=\text{Concentration of }KOH\times \text{Volume of solution}$

$\text{Moles of }KOH=3.00M\times 10.0mL=30mmol=0.03mol$

Now we have to calculate the value of $pK_a$ of the weak acid.

The equilibrium chemical reaction is:

$HA+KOH\rightleftharpoons HK+H_2O$

Initial moles 0.25 0.03 0

At eqm. (0.25-0.03) 0.03 0.03

= 0.22

Using Henderson Hesselbach equation :

$pH=pK_a+\log \frac{[Salt]}{[Acid]}$

$pH=pK_a+\log \frac{[HK]}{[HA]}$

Now put all the given values in this expression, we get:

$3.85=pK_a+\log (\frac{0.03}{0.22})$

$pK_a=4.72$

Therefore, the value of $pK_a$ of the weak acid is, 4.72

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3 years ago

How can you make that the gas' molecules move faster?

Vladimir79 [104]

With an increase in temperature, the particles gain kinetic energy and move faster. (The ANSWER is increase the temperature.)

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3 years ago

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Group 7a of the periodic table contains the

ohaa [14]

A.) Most reactive non-metals

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3 years ago

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Calculate the enthalpy change that occurs when 1.00 kg of acetone condenses at its boiling point (329.4 K). The standard enthalp

zubka84 [21]

Answer:

Option 1 is correct.

ΔH for the condensation of 1 kg of Acetone is - 501 KJ.

Explanation:

Molar mass of acetone = 58.08 g/mol

Number of moles of acetone that condenses = mass/molar mass = 1000/58.08 = 17.22 moles

1 mole of Acetone vaporizer with an enthalpy change of 29.1 KJ.

1 mole of Acetone will condense with an enthalpy change of - 29.1 KJ (since condensation is the exact reverse of vaporization)

That is, vaporization is given by,

Acetone(l) ----> Acetone(g) ΔH = 29.1 KJ

Then condensation will be given by,

Acetone(g) ----> Acetone(l) ΔH = -29.1 KJ

So,

1 mole of Acetone will condense with an enthalpy change of - 29.1 KJ

17.22 moles of Acetone will condense with an enthalpy change of 17.22 × - 29.1 KJ = - 501 KJ.

The first option is correct.

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4 years ago

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When comparing bromine to chlorine, bromine has

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Explanation:

I'm pretty sure the answer is D

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