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3 years ago

36 g of water vapor takes up how many liters at room temperature and pressure of 293K and 100 K PA

Chemistry

2 answers:

qaws [65]3 years ago

7 0

Answer:-

48.72 L

Explanation:-

Chemical formula of water= H2O

Mass of water = 36 g

Molar mass of water = 1 x 2 + 16 x 1 = 18 g mol-1

Number of moles of water = n = 36 g / (18 g mol-1)

= 2 moles.

Temperature T = 293 K

Pressure = P = 100 K Pa

Universal gas constant R = 8.314 L KPa K -1 mol-1

Using the relation PV = nRT

we get Volume V = nRT/P

Plugging in the values

V = (2 moles ) x ( 8.314 L KPa K -1 mol-1) x ( 293 K) / 100 K Pa

= 48.72 L

crimeas [40]3 years ago

6 0

100kpa is correct .100 kpa is correct

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Define molecular formula and empirical formula. What are the similarities and differences between the empirical formula and mole

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<u>Explanation:</u>

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

In both the formulas, the nature of atoms remains the same but the number differs.

For Example: The molecular formula of oxalic acid is $C_2H_2H_4$ but the empirical formula of oxalic acid is $CHO_2$

To calculate the molecular formula, we need to find the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

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3 years ago

The concentration of copper(II) sulfate in one brand of soluble plant fertilizer is 0.070% by weight. If a 21.5 g sample of this

Semmy [17]

Answer:

The molar concentration of $Cu^{2+}$ ions in the given amount of sample is $4.73\times 10^{-5}M$

Explanation:

Given that,

Mass of sample = 21.5 g

0.07 % (m/m) of copper (II) sulfate in plant fertilizer

This means that, in 100 g of plant fertilizer, 0.07 g of copper (II) sulfate is present

So, in 20 g of plant fertilizer

, $=\frac{0.07}{100}\times 21.5}\\=0.0151g$ of copper (II) sulfate is present.

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Mass of solute (copper (II) sulfate) = 0.0151 g

Molar mass of copper (II) sulfate = 159.6 g/mol

Volume of solution = 2.0 L

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$CuSO_4\rightarrow Cu^{2+}+SO_4^{2-}$

1 mole of copper (II) sulfate produces 1 mole of copper (II) ions and sulfate ions

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3 years ago

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Leto [7]

Answer:

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3 years ago

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Alinara [238K]

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3 years ago

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