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4 years ago

36 g of water vapor takes up how many liters at room temperature and pressure of 293K and 100 K PA

Chemistry

2 answers:

qaws [65]4 years ago

7 0

Answer:-

48.72 L

Explanation:-

Chemical formula of water= H2O

Mass of water = 36 g

Molar mass of water = 1 x 2 + 16 x 1 = 18 g mol-1

Number of moles of water = n = 36 g / (18 g mol-1)

= 2 moles.

Temperature T = 293 K

Pressure = P = 100 K Pa

Universal gas constant R = 8.314 L KPa K -1 mol-1

Using the relation PV = nRT

we get Volume V = nRT/P

Plugging in the values

V = (2 moles ) x ( 8.314 L KPa K -1 mol-1) x ( 293 K) / 100 K Pa

= 48.72 L

crimeas [40]4 years ago

6 0

100kpa is correct .100 kpa is correct

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How many grams are in 3 mol of KBr?

e-lub [12.9K]

Answer: 7

Explanation:

6 0

4 years ago

Read 2 more answers

The balanced redox reactions for the sequential reduction of vanadium are given below.

Minchanka [31]

Answer : 0.0392 grams of Zn metal would be required to completely reduced the vanadium.

Explanation :

Let us rewrite the given equations again.

$2VO_{2}^{+} (aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2VO^{2+}(aq)+Zn^{2+}+2H2O(l)$ $2VO^{2+}(aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2V^{3+} (aq)+Zn^{2+}+2H2O(l)$

$2V^{3+} (aq)+ Zn (s)\rightarrow 2V^{2+}(aq)+Zn^{2+}(aq)$

On adding above equations, we get the following combined equation.

$2VO_{2}^{+} (aq)+ 8H^{+} (aq) + 3Zn (s)\rightarrow 2V^{2+}(aq)+3Zn^{2+}(aq)+4H_{2}O(l)$

We have 12.1 mL of 0.033 M solution of VO₂⁺.

Let us find the moles of VO₂⁺ from this information.

$12.1 mL \times \frac{1L}{1000mL}\times \frac{0.033mol}{L}=0.0003993mol NO_{2}^{+}$

From the combined equation, we can see that the mole ratio of VO₂⁺ to Zn is 2:3.

Let us use this as a conversion factor to find the moles of Zn.

$0.0003993mol NO_{2}^{+}\times \frac{3mol Zn}{2molNO_{2}^{+}}=0.00059895mol Zn$

Let us convert the moles of Zn to grams of Zn using molar mass of Zn.

Molar mass of Zn is 65.38 g/mol.

$0.00059895mol Zn\times \frac{65.38gZn}{1molZn}=0.0392gZn$

We need 0.0392 grams of Zn metal to completely reduce vanadium.

6 0

3 years ago

When two atoms form a covalent bond, they share electrons from all of their orbitals. All of their orbitals, in turn, combine to

erma4kov [3.2K]

Answer:

It's false.

Explanation:

Molecular orbital theory states that the number of molecular orbitals is equal to the number of atomic orbitals that overlap. The lowest energy molecular orbital is formed when two atomic orbitals that are in phase overlap, forming a bonding molecular orbital. However, another molecular orbital is also formed, called an anti-binding orbital.

So if an "n" quantity of atomic orbitals is combined, an "n" quantity of molecular orbitals is formed.

Have a nice day!

8 0

4 years ago

How many milliliters of manganese metal, with a density of 7.43 g/mL, would be needed to produce 21.7 grams of hydrogen gas in t

Alla [95]

First compute the number of grams of manganese metal required to make 21.7 grams of H2.
21.7 g H2 x (1 mole H2/ 2 g H2) x (1 mole Mn/1 mol H2) x (55 grams Mn/1 mol Mn) = 596.75 grams
Now density = mass/volume
7.43 = 596.75/volume
volume = 596.75/7.43 = 80.31 mL
80.31 mL is the amount of manganese needed.

3 0

3 years ago

Given a fixed amount of gas held at constant pressure, calculate the volume (in L) it would occupy if a 3.50 L sample were coole

Over [174]

Answer:

V₂ = 2.91 L

Explanation:

Given data:

Initial volume = 3.50 L

Initial temperature = 90.0°C (90+273 = 363 K)

Final temperature = 30.0 °C ( 30 +273 = 303 K)

Final volume = ?

Solution:

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

V₁/T₁ = V₂/T₂

3.50 L / 363 K) = V₂ / 303 K)

V₂ = 0.0096 L/K × 303 K

V₂ = 2.91 L

6 0

3 years ago