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3 years ago

The table below gives the numbers of protons, electrons, and neutrons in four atoms.

Chemistry

2 answers:

PolarNik [594]3 years ago

4 0

Answer:

Atom 3

Explanation:

Protons have a +1 charge, electrons have a -1 charge, and neutrons have no charge and are therefore neutral. The charges will cancel each other when equal. To determine which atom has the a -1 charge, find the atom that has one more electron than it has protons.

Nana76 [90]3 years ago

4 0

Question:

Based on the table, which atom has a charge of –1?

Answer:

Atom 3

Explanation:

I took the test on Edgenuity (2020) and got it correct. Hope this helps you! :)

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A. Gallium is produced by the electrolysis of a solution obtained by dissolving gallium oxide in concentrated NaOH(aq). Calculat

liraira [26]

Answer:

A)Mass of gallium plated out is 0.3440 grams

B) For 0.67 hours current of 5.79 A must to be applied to plate out 8.70 g of tin.

Explanation:

To calculate the total charge, we use the equation:

$C=I\times t$

where,

C = Charge

I = Current in time t (seconds)

To calculate the moles of electrons, we use the equation:

$\text{Moles of electrons}=\frac{C}{F}$

where,

F = Faraday's constant = 96500

A) The equation for the deposition of Ga(s) from Ga(III) solution follows:

$Ga^{3+}(aq.)+3e^-\rightarrow Ga(s)$

I = 0.790 A, t = 30.0 min = 1800 seconds

$C=I\times t$

$C=0.790 A\times 1800 s=1422 C$

Moles of electron transferred:

$=\frac{1422 C}{96500 F}=0.01474 mol$

Now, to calculate the moles of gallium, we use the equation:

$\text{Moles of Gallium}=\frac{\text{Moles of electrons}}{n}$

n = number of electrons transferred = 3

$\text{Moles of Gallium}=\frac{0.01474 mol}{3}=0.004913 mol$

Mass of 0.004913 moles of gallium = 0.004913 mol × 70 g/mol=0.3440 g

B) The equation for the deposition of Sn(s) from Sn(II) solution follows:

$Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)$

Moles of tin = $\frac{8.70 g}{119 g/mol}=0.07311 mol$

n = number of electrons transferred = 2

$\text{Moles of tin}=\frac{\text{Moles of electrons}}{n}$

Moles of electron = $n\times \text{Moles of tin}$

$=2\times 0.07311 mol=0.14622 mol$

Charge transferred during time t :

$\text{Moles of electrons}=\frac{C}{F}$

$C=96500 F\times 0.14622 mol=14,110.23 C$

Current applied for t time = I = 5.79 A

$t=\frac{C}{I}=\frac{14,110.23 C}{5.79 A}=2,437 s=0.67 hrs$

For 0.67 hours current of 5.79 A must to be applied to plate out 8.70 g of tin.

5 0

3 years ago

Right now I’m a freshmen, and we got our scheduling paper for next year as sophomores. I’m wondering if I should take chemistry

Anastasy [175]

Anatomy I think it's important to know anatomy as a young adult so u are self aware of your body

3 0

3 years ago

Read 2 more answers

A 0.875-g sample of anthracite coal was burned in a bomb calorimeter. The temperature rose from 22.50 to 23.80°C. The heat capac

kherson [118]

Answer:

a) 26.65 kJ was the heat evolved by the reaction.

b) $3.046\times 10^7 kJ$ is the energy released on burning 1 metric ton of this type of coal

Explanation:

Heat capacity of the calorimeter = C = 20.5 kJ/°C

Initial temperature of the calorimeter, $T_1$ = 22.50°C

Final temperature of the calorimeter, $T_2$ = 23.80°C

The heat evolved by the reaction = Q

$Q=C(T_2-T_1)$

$Q=20.5 kJ/^oC\times (23.80^oC-22.50^oC)$

$Q=26.65 kJ$

26.65 kJ was the heat evolved by the reaction.

0.875 g sample of anthracite coal was burned in a bomb calorimeter

0.875 g sample of anthracite coal gives 26.65 kJ of heat.

1 metric ton= 1000 kg

1000 kg = 1000 × 1000 g = 1,000,000 (1 kg =1000 g)

Then burning 1,000,000 g coal will give:

$=\frac{26.65 kJ }{0.875}\times 1,000,000 g=3.046\times 10^7 kJ$

$3.046\times 10^7 kJ$ is the energy released on burning 1 metric ton of this type of coal

8 0

3 years ago

Which of the materials above are mixtures

madam [21]

Answer:

water and vinegar

:salad

Explanation:

There is two kind of mixture the heterogeneous and homogeneous mixture.Which water and vinegar is the homogeneous and the salad is heterogeneous mixture based on my example above.

7 0

3 years ago

(b) Why must acidic gases be treated before they are released into the atmosphere?

Inga [223]

Answer:

because they react with other gases of atmosphere and pollute the environment

8 0

3 years ago