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3 years ago

Density is found by dividing ____.

Physics

2 answers:

kirza4 [7]3 years ago

7 0

The correct answer is mass by volume

bezimeni [28]3 years ago

6 0

Mass represents the density of an object multiplied with the volume it occupies. As a result, an object's density is found by dividing its mass by its volume. So the answer is a.

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Kung hatiin sa tatlong pangkat ng 72 na bata isang bata mayroon sa bawat pangkat desisyon sentence

podryga [215]

Answer:

ewan ko papano bato pukinag ina

Explanation:

gagu ka kase putangina mo

8 0

3 years ago

Light of wavelength 648.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 57.5 cm from the slit.

boyakko [2]

Answer:

$71.0 \mu m$

Explanation:

The formula for the single-slit diffraction is

$y=\frac{n\lambda D}{d}$

where

y is the distance of the n-minimum from the centre of the diffraction pattern

D is the distance of the screen from the slit

d is the width of the slit

$\lambda$ is the wavelength of the light

In this problem,

$\lambda=648.0 nm=6.48\cdot 10^{-7}m$

$D=57.5 cm=0.575 m$

$y=1.05 cm=0.0105 m$ , with n=2 (this is the distance of the 2nd-order minimum from the central maximum)

Solving the formula for d, we find:

$d=\frac{n\lambda D}{y}=\frac{2(6.48\cdot 10^{-7} m)(0.575 m)}{0.0105 m}=7.10\cdot 10^{-5} m= 71.0 \mu m$

6 0

3 years ago

Which force is a field force?

jok3333 [9.3K]

it has to me c because it’s a part of the force of things that do

7 0

3 years ago

Read 2 more answers

An eagle is flying above a mountain of height 2,700 m above sea level. Calculate the pressure on the eagle if the average densit

nadya68 [22]

Answer:

The correct option is;

(A) 25.8 cmHg

Explanation:

The given parameters are;

The height of the mountain over which the eagle is flying = 2700 m

The average density of air, ρₐ = 1.3 kg/m³

The atmospheric pressure at sea level = 76 cmHg = 0.76 mHg

The density of mercury, $\rho _m$ = 13,600 kg/m³

The formula for pressure, p, is p = ρ·g·h

The pressure in the atmosphere = 13,600 × 0.76 × g = 10,336·g

The equivalent height of air is found as follows;

1.3 × g × h = 10,336·g

h = 10,336/1.3 = 7,950.769 meters

Therefore;

The pressure of the atmosphere at 2,700 meters, p₂₇₀₀ = (2,700/7,950.769) × 76 cm Hg

Which gives;

p₂₇₀₀ = 25.808 cmHg ≈ 25.8 cmHg.

3 0

3 years ago

If you triple the speed from 20km/h to 60km/h, by what factor does the KE increase?

sertanlavr [38]

Answer:

The kinetic energy increases by a factor of 9

Explanation:

Kinetic Energy

It's the energy related to the speed of an object and is calculated by the formula

$\displaystyle K=\frac{mv^2}{2}$

Let's suppose the initial speed of the mass is $v_o$ , then the kinetic energy is

$\displaystyle K_o=\frac{mv_o^2}{2}$

Now the speed will triple, i.e. $v_1=3v_o$ . The new kinetic energy is

$\displaystyle K_1=\frac{mv_1^2}{2}$

$\displaystyle K_1=\frac{m(3v_o)^2}{2}$

$\displaystyle K_1=9\frac{mv_o^2}{2}$

Thus

$K_1=9K_o$

The kinetic energy increases by a factor of 9

Let's check with numbers: $v_o=20,\ v_1=60$

$\displaystyle K_o=\frac{m20^2}{2}=200m$

$\displaystyle K_1=\frac{m60^2}{2}=1800m$

The relation is

$\displaystyle \frac{K_1}{K_o}=9$

The new kinetic energy is nine times the initial kinetic energy.

5 0

3 years ago