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tankabanditka [31]
3 years ago
15

If you triple the speed from 20km/h to 60km/h, by what factor does the KE increase?

Physics
1 answer:
sertanlavr [38]3 years ago
5 0

Answer:

<em>The kinetic energy increases by a factor of 9 </em>

Explanation:

<u>Kinetic Energy </u>

It's the energy related to the speed of an object and is calculated by the formula

\displaystyle K=\frac{mv^2}{2}

Let's suppose the initial speed of the mass is v_o, then the kinetic energy is

\displaystyle K_o=\frac{mv_o^2}{2}

Now the speed will triple, i.e. v_1=3v_o. The new kinetic energy is

\displaystyle K_1=\frac{mv_1^2}{2}

\displaystyle K_1=\frac{m(3v_o)^2}{2}

\displaystyle K_1=9\frac{mv_o^2}{2}

Thus

K_1=9K_o

The kinetic energy increases by a factor of 9

Let's check with numbers: v_o=20,\ v_1=60

\displaystyle K_o=\frac{m20^2}{2}=200m

\displaystyle K_1=\frac{m60^2}{2}=1800m

The relation is

\displaystyle \frac{K_1}{K_o}=9

The new kinetic energy is nine times the initial kinetic energy.

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<h3>What is Acceleration ?</h3>

Acceleration can be defined as change in velocity per time taken. It is a vector quantity. That is, it has both the magnitude and direction. It is measured in m/s²

Given that a velocity of a car decreases from 28m/s to 20m/s in a time of 4 seconds. Then,

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