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2 years ago

an object is placed in front of a curved mirror as shown. which of the labeled positions is the current position of the image

Physics

2 answers:

alexandr402 [8]2 years ago

4 0

Answer:A

Explanation:

The image is formed behind the mirror.

Lilit [14]2 years ago

4 0

Answer:

Explanation:

took the test

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Translate the word phrase into an algebraic equation: the quotient of 22 and 2 is equal to 11.

Solnce55 [7]

Answer:

22/2 = 11

Explanation:

A quotient means the result of a division problem. When it says the quotient of a and b, this means of "a divided by b". Remember to always go in the right order, because in division, order matters.

Therefore the quotient of 22 and 2 is equal to 11 is written: 22/2 = 11

7 0

2 years ago

Calculate the average velocity of a dancer who moves 5 m toward the left of the stage over the course of 15 s. ** Velocity = dis

Alex73 [517]

Answer:

Explanation:

Velocity=disp/time

V=5m/15s

V=1/3 m/s

3 0

3 years ago

Which is NOT a waste that is removed from the body by the excretory system?

oksian1 [2.3K]

Answer:

C. Blood

Explanation:

All the other ones are removed from the body normally.

8 0

3 years ago

Read 2 more answers

Which process is responsible for changing the composition of rock?

Crazy boy [7]

Erosion, weathering, mechanical changes, chemical changes.

Really, any interaction can change the composition of a rock whether it be done by man or through nature.

4 0

3 years ago

Read 2 more answers

A seagull flies at a velocity of 9.00 m/s straight into the wind. (a) if it takes the bird 20.0 min to travel 6.00 km relative t

enot [183]

Here we will the speed of seagull which is v = 9 m/s

this is the speed of seagull when there is no effect of wind on it

now in part a)

if effect of wind is in opposite direction then it travels 6 km in 20 min

so the average speed is given by the ratio of total distance and total time

$v_{avg} = \frac{6000}{20*60}$

$v_{avg} = 5m/s$

now since effect of wind is in opposite direction then we can say

$V_{net} = v_{bird} - v_{wind}$

$5 = 9 - v_{wind}$

$v_{wind}= 4 m/s$

Part b)

now if bird travels in the same direction of wind then we will have

$v_{net}= v_{bird} + v_{wind}$

$v_{net} = 9 + 4 = 13 m/s$

now we can find the time to go back

$time = \frac{distance}{speed}$

$time = \frac{6000}{13}$

$time = 7.7 minutes$

Part c)

Total time of round trip when wind is present

$T = t_1 + t_2$

$T = 20 + 7.7 = 27.7 min$

now when there is no wind total time is given by

$T = \frac{6000}{9} + \frac{6000}{9}$

$T = 22.22 min$

So due to wind time will be more

4 0

3 years ago