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posledela
4 years ago
11

Use the temperatures box-and-whisker plot to solve. What are the quartiles of the data? A. lower quartile (Q1) = 14 median (Q2)

= 22 upper quartile (Q3) = 27 B. lower quartile (Q1) = 12 median (Q2) = 22 upper quartile (Q3) = 30 C. lower quartile (Q1) = 14 median (Q2) = 20 upper quartile (Q3) = 27 D. lower quartile (Q1) = 14 median (Q2) = 22 upper quartile (Q3) = 26
Physics
2 answers:
blondinia [14]4 years ago
6 0
Use the temperatures box-and-whisker plot to solve. What are the quartiles of the data? D. Is the correct answer, Hope I helped, and good luck!
Semenov [28]4 years ago
4 0
 D. lower quartile (Q1) = 14 median (Q2) = 22 upper quartile (Q3) = 26
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A nearsighted person wants to see an apple that is 7 meters away but can only clearly see objects that are at most 62 cm away fr
natulia [17]

Answer:

The power of the corrective lenses is 3.162 D.

Explanation:

Given that,

Object distance = 70 cm

Image distance = 62 cm

Distance between eyes and glasses = 2.5 cm

Eyeglasses made of diverging corrective lenses can help her to see the apple clearly

So now ,

Object distance from glass =70-2.5 = 67.5 cm

Image distance from glass = 62-2.5 = 59.5 cm

We need to calculate the focal length

Using formula for focal length

\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}

\dfrac{1}{f}=-\dfrac{1}{59.5}-\dfrac{1}{67.5}

\dfrac{1}{f}=-\dfrac{508}{16065}\ cm

We need to calculate the power of lens

Using formula of power

P=\dfrac{100}{f}

P=-\dfrac{508}{16065}\times100

P=-3.162 \ D

Negative sign shows the lens is diverging.

Hence, The power of the corrective lenses is 3.162 D.

6 0
4 years ago
What do the vertical columns in the periodic table indicate?
romanna [79]

The correct answer is

D. Groups and Families

I did the quiz nd this was the right answer

Hopes this helps :)


3 0
3 years ago
Read 2 more answers
If the torque required to loosen a nut that holds a wheel on a car has a magnitude of 55 n·m, what force must be exerted at the
erastova [34]

Either 175 N or 157 N depending upon how the value of 48° was measured from.    
You didn't mention if the angle of 48° is from the lug wrench itself, or if it's from the normal to the lug wrench. So I'll solve for both cases and you'll need to select the desired answer.    
Since we need a torque of 55 N·m to loosen the nut and our lug wrench is 0.47 m long, that means that we need 55 N·m / 0.47 m = 117 N of usefully applied force in order to loosen the nut. This figure will be used for both possible angles.    
Ideally, the force will have a 0° degree difference from the normal and 100% of the force will be usefully applied. Any value greater than 0° will have the exerted force reduced by the cosine of the angle from the normal. Hence the term "cosine loss".     
If the angle of 48° is from the normal to the lug wrench, the usefully applied power will be:  
U = F*cos(48)  
where  
U = Useful force  
F = Force applied    
So solving for F and calculating gives:  
U = F*cos(48)  
U/cos(48) = F  
117 N/0.669130606 = F  
174.8537563 N = F    
So 175 Newtons of force is required in this situation.    
If the 48° is from the lug wrench itself, that means that the force is 90° - 48° = 42° from the normal. So doing the calculation again (this time from where we started plugging in values) we get  
U/cos(42) = F  
117/0.743144825 = F  
157.4390294 = F    
Or 157 Newtons is required for this case.
6 0
3 years ago
Caculate the total charge transferred through a wire carrying a current of 0.5 Ameter for a period of 20 seconds.
Marina CMI [18]

charge = current x time = 0.5x 20=10Coulombs

5 0
3 years ago
A cupboard is placed in front of a heater. Air can move through a gap under the cupboard.
expeople1 [14]

Answer:

B

Explanation:

7 0
3 years ago
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