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konstantin123 [22]
3 years ago
9

How long will it take a projectile to hit the ground if it is launched at 4.2 m/s off a 12.6 m high platform?

Physics
1 answer:
8090 [49]3 years ago
6 0

Answer: 3

Explanation:

I think you are supposed to divided in those problems? I'm not sure but if you aren't then please let me know. The equation I did was:

12.6 / 4.2 = 3

Hope this helps!! :)

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The mathematical relationship between current, voltage and resistance is known as
stiks02 [169]

Answer:

Ohm's Law

Explanation:

The relationship: V=R*I

where V represents the voltage across a resistor of resistance "R" through which a current (I) flows,

is known as Ohm's Law in honor of Georg Ohm, who discover this proportionality.

3 0
3 years ago
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Which conclusion about the atom can be drawn from Rutherford’s gold foil experiment?
Drupady [299]
D. Rutherford found that the atom consists of a small positively charged nucleus.
6 0
3 years ago
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What is the electric flux ΦΦPhi through each of the six faces of the cube?
BlackZzzverrR [31]

Flux through each of the six faces of the cube: \frac{q}{6\epsilon_0}

Explanation:

In this problem, a charge q is placed at the center of the cube.

We can apply Gauss Law, which states that the flux through the surface of the cube is equal to the charge contained within the cube divided by the vacuum permittivity; mathematically:

\Phi_T=\frac{q}{\epsilon_0}

where

q is the charge

\epsilon_0 is the vacuum permittivity

Here we want to find the flux through each of the six faces of the cube.

By simmetry, we can say that the 6 faces are identical: therefore, the flux through each of them must be the same. This means that the flux  through each faces is 1/6 of the total flux through the total surface, therefore:

\Phi = \frac{1}{6}\Phi = \frac{q}{6\epsilon_0}

Learn more about electric fields:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

8 0
3 years ago
In measuring the width of a hair sample, a light of wavelength 500 nm is used. The hair sample is 40 um in radius. With the scre
sergejj [24]

Answer:

The distance of the second dark band away from the central bright spot be located is 5.625\times10^{-2}\ m

Explanation:

Given that,

Wave length = 500 nm

Radius d= 40\ \mu m

Distance from the hair sample D= 6 m

We need to calculate the distance of the second dark band away from the central bright spot be located

\sin\theta=\dfrac{y}{D}

\sin\theta=\dfrac{y}{6}

Using formula for dark fringe

(n-\dfrac{1}{2})\lambda=2d\sin\theta

Put the value into the formula

(2-\dfrac{1}{2})\times500\times10^{-9}=2\times40\times10^{-6}\times\dfrac{y}{6}

y=\dfrac{(2-\dfrac{1}{2})\times500\times10^{-9}\times6}{2\times40\times10^{-6}}

y=0.05625\ m

y=5.625\times10^{-2}\ m

Hence, The distance of the second dark band away from the central bright spot be located is 5.625\times10^{-2}\ m

6 0
3 years ago
I WOULD APPRECIATE HELP :)
Harlamova29_29 [7]

Answer:

Water vapor- least dense

liquid water- bonds

ice- most dense

Explanation:

I'm pretty sure lol

4 0
3 years ago
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