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mr_godi [17]
3 years ago
14

Determine the following quantities for the circuits shown below:

Physics
1 answer:
madam [21]3 years ago
8 0

Answer:

a) 588.235 ohm ( all the 3 resistors are in parallel )

b) 10 A

c) Current flowing -

in 20 ohm resistor = 6.25 A

in 100 ohm resistor = 1.25 A

in 50 ohm resistor = 2.5 A

d) Voltage drop across all the resistor = 125 V

(As all the resistors are in parallel all the resistors will have the same voltage drop )

e) Power dissipated -

in 20 ohm resistor = 781.25 W

in 100 ohm resistor = 156.25 W

in 50 ohm resistor = 312.5 W

(Power = Current × Potential Difference)

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How many joules of energy are required to accelerate one kilogram of mass from rest to a velocity of 0.866c?
Arlecino [84]

Answer:

the amount of energy needed is 1.8 x 10¹⁷ J.

Explanation:

Given;

mass of the object, m₀ = 1 kg

velocity of the object, v = 0.866 c

By physics convection, c is the speed of light = 3 x 10⁸ m/s

The energy needed is calculated as follows;

E = Mc²

As the object approaches the speed of light, the change in the mass of the object is given by Einstein's relativity formula;

M = \frac{M_0}{\sqrt{1- \frac{v^2}{c^2} } } \\\\  M = \frac{1}{\sqrt{1- \frac{(0.866c)^2}{c^2} } }\\\\  M = \frac{1}{\sqrt{1- \frac{0.74996c^2}{c^2} } }\\\\  M = \frac{1}{\sqrt{0.25} } \\\\ M = 2 \ kg

The energy required is calculated as;

E = 2 x (3 x 10⁸)²

E = 1.8 x 10¹⁷ J

Therefore, the amount of energy needed is 1.8 x 10¹⁷ J.

3 0
3 years ago
A(n) 69.8 kg astronaut becomes separated from the shuttle, while on a space walk. She finds herself 60.4 m away from the shuttle
alukav5142 [94]

Answer:

The time taken is 6.7  min

Explanation:

Using the linear momentum conservation theorem, we have:

m_1*v_{o1}+m_2*v_{o2}=m_1*v_{f1}+m_2*v_{f2}

when she was 60.4m from the shuttle, she has zero speed, so the initial velocity is zero.

m_1*0+m_2*0=m_1*v_{f1}+m_2*v_{f2}\\m_1*_{f1}=-m_2*v_{f2}\\v_{f1}=-\frac{m_2*v_{f2}}{m_1}\\\\v_{f1}=-\frac{0.886kg*12m/s}{69.8kg}\\\\V_{f1}=-0.15m/s

That is 0.15m/s in the opposite direction of the camera.

the time taken to get to the shuttle is given by:

t=\frac{d}{v_{f1}}\\\\t=\frac{60.4m}{0.15m/s}\\\\t=403s\\t_{min}=403s*\frac{1min}{60s}=6.7min

6 0
3 years ago
Communicate the results
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What results do we communicate?
6 0
4 years ago
Which of the following best describes applying a force over a period of time?
Mazyrski [523]
Impulse
it’s the only one that makes sense energy is just light and power almost the same thing
7 0
3 years ago
At a particular instant, a stationary observer on the ground sees a package falling with speed v1 at an angle to the vertical. t
Lerok [7]
V1 * sin(θ) where θ is the angle v1 makes with the vertical.
7 0
4 years ago
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