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marishachu [46]
3 years ago
14

Interactive LearningWare 10.1 reviews the concepts involved in this problem. A spring stretches by 0.0161 m when a 3.74-kg objec

t is suspended from its end. How much mass should be attached to this spring so that its frequency of vibration is f = 3.84 Hz?
Physics
1 answer:
yKpoI14uk [10]3 years ago
8 0

Answer:

m = 3.91 kg

Explanation:

Given that,

Mass of the object, m = 3.74 kg

Stretching in the spring, x = 0.0161 m

The frequency of vibration, f = 3.84 Hz

When the object is suspended, the gravitational force is balanced by the spring force as :

mg=kx

k=\dfrac{mg}{x}

k=\dfrac{3.74\times 9.8}{0.0161}

k = 2276.52 N/m

The frequency of vibration is given by :

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

m=\dfrac{k}{4\pi^2f^2}

m=\dfrac{2276.52}{4\pi^2\times (3.84)^2}

m = 3.91 kg

So, the mass of the object is 3.91 kg. Hence, this is the required solution.

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Answer:

The value is \lambda  =  2 \  m

Explanation:

From the question we are told that

     The distance of the speaker  from the  second speaker  to the east is  d = 3 \  m

      The distance of the speaker  from the listener  to the south is     a = 4 \  m

Generally given that if the speaker move in any direction, their sound become  louder , it then mean that the position of the listener of minimum sound (i.e a position of minima ) ,

Generally the path difference of the sound produce by both speaker at a position of minima is mathematically represented as

              y =  \frac{\lambda}{2}

Generally considering the orientation  of the speakers and applying Pythagoras theorem we see that  distance from the second speaker to the listener  is mathematically represented as

             b =  \sqrt{d^ 2 + a^2 }

=>           b =  \sqrt{3^ 2 + 4^2 }

=>           b = 5

Generally the path difference between the two speaker with respect to the  listener is  

              y =  b - a

=>           y = 5 - 4

=>           y = 1

So  

              1 =  \frac{\lambda}{2}

=>           \lambda  =  2 \  m

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3 years ago
What is the equation for frequency?
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Answer:

f=1/t is the equation of frqency

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g A raindrop charged to 10 mC experiences electric field of 10,000 V/m from a tip of a tree branch. What is the electric force a
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Answer:

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Explanation:

Given;

charge of the raindrop, Q = 10 mC = 0.01 C

electric field strength, E = 10,000 V/m = 10,000 N/C

The force acting on the raindrop is given as;

Electric Force = electric field strength x charge of the raindrop

F = EQ

F = (10,000 N/C) (0.01 C)

F = 100 N

Therefore, the electric force acting on the raindrop is 100 N.

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The differences between microwaves and infrared radiation are due to differences in their _____.
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Answer:

15 V

Explanation:

From the question,

For series connection: (i) Both resistor have a common current flowing through the (ii) The combined resistance = R1+R2

Rt = R1+R2.................. Equation 1

Given: R1 = 5 ohms, R2 = 7.5 ohms.

Rt = 5+7.5 = 12.5 ohms.

Applying Ohm's law,

V = IRt................... Equation 2

Where V = Voltage, I = current.

make I The subject of the equation

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Given: V = 25 V, Rt = 12.5 ohms.

Substitute into equation 3

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Voltage drop across the 7.5 ohms resistor = 7.5×2

Voltage drop across the 7.5 ohms resistor = 15 V

8 0
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