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ArbitrLikvidat [17]
3 years ago
10

Determine the number of centiliters in 2.4 x 10^3 milliliters.

Chemistry
1 answer:
AnnZ [28]3 years ago
8 0
2.4(10^3)

=2.4*10^3

=2.4*(10*10*10)

=2400 <span>milliliters

To </span>centiliters is<span> 2400mL= <u>240.0000cl. </u> </span>



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Write the cell notation for an electrochemical cell consisting of an anode where Mn (s) is oxidized to Mn2 (aq) and a cathode wh
morpeh [17]

Answer:

Mn(s)/Mn^2+(aq)//Co^2+(aq)/Co(s)

Explanation:

In writing the cell notation for an electrochemical cell, the anode is written on the left hand side while the cathode is written on the right hand side. The two half cells are separated by two thick lines which represents the salt bridge.

For the cell discussed in the question; the Mn(s)/Mn^2+(aq) is the anode while the Co^2+(aq)/Co(s) half cell is the cathode.

Hence I can write; Mn(s)/Mn^2+(aq)//Co^2+(aq)/Co(s)

8 0
3 years ago
Origin of hard water​
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Explanation:

7 0
3 years ago
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Calculate the moles and grams of solute in 2.0 L of 0.30M Na SO..
Ostrovityanka [42]

Answer:

Number of moles of solute = 0.6 mole

Mass =13.8 g

Explanation:

Given data:

Number of moles of sodium = ?

Volume = 2.0 L

Molarity = 0.30 M

Mass in gram of sodium= ?

Solution:

<em>Number of moles:</em>

Molarity = number of moles of solute / volume in litter

Number of moles of solute = Molarity × volume in litter

Number of moles of solute = 0.30 M × 2.0 L

Number of moles of solute = 0.6 mole

<em>Mass in gram:</em>

Mass = Number of moles × molar mass

Mass = 0.6 mole× 23 g/mol

Mass =13.8 g

3 0
3 years ago
Please and thank you!
Valentin [98]

Answer:

7.5 moles of O₂.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2KClO₃ —> 2KCl + 3O₂

From the balanced equation above,

2 moles of KClO₃ decomposed to produce 3 moles of O₂.

Finally, we shall determine the number of mole of O₂ produced by the decomposition of 5 moles of KClO₃. This can be obtained as follow:

From the balanced equation above,

2 moles of KClO₃ decomposed to produce 3 moles of O₂.

Therefore, 5 moles of KClO₃ will decompose to produce = (5 × 3)/ 2 = 7.5 moles of O₂.

Thus, 7.5 moles of O₂ were obtained from the reaction.

3 0
3 years ago
What's the empirical and molecular weight of C14H22N4O8? What's the molecular formula of C14H22N4O8?
Inessa05 [86]

374u

187u

C₁₄H₂₂N₄O₈

Explanation:

To find the molecular weight of the compound C₁₄H₂₂N₄O₈ we simply sum that atomic masses of the given elements in the compound.

 The empirical weight is determined by using the simplest ratio of the elements involved in the compound;

Molecular weight of C₁₄H₂₂N₄O₈;

atomic mass of C = 12g/mol

                           H = 1g/mol

                            N = 14g/mol

                            O = 16g/mol

 Molecular weight = 14(12) + 22(1) + 4(14) + 8(16)

                                = 168 + 22 + 56 + 128

                                 = 374u

Empirical weight:

  Empirical formula:

                        C₁₄    H₂₂      N₄     O₈

                         14  :    22 :    4  :     8

   divide by 2:

                          7   :    11    :    2  :    4

     empirical formula  C₇H₁₁N₂O₄

     empirical weight = \frac{molecular weight}{2} = \frac{374}{2} = 187u

The molecular formula is the actual combination of atoms in a compound. so the molecular formula of the compound is C₁₄H₂₂N₄O₈

learn more:

Molecular mass brainly.com/question/5546238

#learnwithBrainly

8 0
3 years ago
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