His is a step down transformer since n(primary) is greater than n(seconcary). You relate the input voltage with the ouput voltage with the following equation:
<span>Vout = n2/n1*Vin (n2/n1 is essentially your 'transfer function' that dictates what a specified input would produce) </span>
<span>Solving the equation: </span>
<span>Vin = Vout*n1/n2 = (320V)*(600/300) = 640 V </span>
<span>This is checked by seeing if Vin is greater than Vout, which it is for a step down transformer.</span>
Answer:
(a) burnout speed at apogee in the external tank disposal orbit=7.82 km/sec
(b) ΔV required for the OMS-1 =0.066 km/sec
(c) ΔV required for the OMS-2 =0.045 km/sec
(d) This part of the question is explained in detailed way in the attached file.
Explanation:
Detailed explanation of all the parts of the question are given in attached files.
Answer:
for C-Cl bond 
for O-O bond 
Explanation:
- We have the bond enegy for C-Cl,

- bond enegy for C-Cl,

<u>Now as we know the energy of electromagnetic waves is given by:</u>

here E = BE
<u>Then for C-Cl:</u>


Now wavelength:



<u>For O2:</u>


Now wavelength:



Answer:
it will take for the sphere to increase in potential by 1500 V, 503.71 s.
Explanation:
The charge on the sphere after t seconds is:
q = (1.0000049 - 1.0000000) t = 0.0000049 t
The voltage on the surface is
V = k *
= k 0.0000049 t / R
solve for t
t = (R*V) / (0.0000049 k) = (0.12 * 1500) / (0.0000049 *
) = 503.71 s
Answer:
true
Explanation:
a body can only be accelerating and have speed if it's in motion