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maw [93]
4 years ago
10

Technician A says the manual lever position (MLP) switch is sometimes called a transmission range switch or a neutral safety swi

tch. Technician B says a MLP switch monitors transmission fluid levels. Who is correct?
A. Technician A only
B. Technician B only
C. Both A and B
D. Neither A nor B
Physics
1 answer:
Phantasy [73]4 years ago
3 0

Answer:

i think it is Technician a

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The two fields of study the principles of biomechanics come from physics and engineering. Biomechanics studies mechanical laws and living organisms. The correct answer is B. 
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How do you do to your question to see if its answered?
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Go in notifications, it'll show if it was answered. If it doesn't show that a person answered it, wait a while, someone might respond :)

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A paint brush is dropped from the top of a tall ladder and free falls to the ground. What changes, if any, would be observed of
muminat

Answer:

Explanation:

As the paint brush is dropped from the top of a tall ladder it started free falling

i.e. velocity of brush increases as it falls down due to the acceleration provided by gravity.

We know acceleration due to gravity is the attraction experienced by the object due to earth attraction

Value of acceleration due to gravity is constant i.e. 9.8\ m/s^2

Therefore the correct choice is

velocity is increasing and acceleration is constant

4 0
4 years ago
Particle 1 has mass 4.6 kg and is on the x-axis at x = 5.7 m. Particle 2 has mass 7.2 kg and is on the y-axis at y = 4.2 m. Part
Iteru [2.4K]

To solve this problem it is necessary to apply the concepts related to the Gravitational Force, for this purpose it is understood that the gravitational force is described as

F_g = \frac{Gm_1m_2}{r^2}

Where,

G = Gravitational Universal Force

m_i = Mass of each object

To solve this problem it is necessary to divide the gravitational force (x, y) into the required components and then use the tangent to find the angle generated between both components.

Our values are given as,

m_1 =4.6 kg\\m_2 = 7.2 kg\\m_3 = 2.6 kg\\r_1 = 5.7 m\\r_2 = 4.2 m

Applying the previous equation at X-Axis,

F_x = \frac{Gm_1m_3}{R_{1}^2}\\F_x = \frac{6.67*10^{-11}*4.6*2.6}{5.7^2}\\F_x = 2.46*10^{-11}N

Applying the previous equation at Y-Axis,

F_y = \frac{Gm_2m_3}{R_2^2}\\F_y = \frac{6.67*10^{-11}*7.2*2.6}{4.2^2}\\F_y = 7.08*10^{-11} N

Therefore the angle can be calculated as,

tan\theta = \frac{F_y}{F_x}\\\theta = tan^{-1} \frac{F_y}{F_x}\\\theta = tan^{-1} \frac{7.08*10^{-11}}{2.46*10^{-11}}\\\theta = 71\°

Then in the measure contrary to the hands of the clock the Force in the particle 3 is in between the positive direction of the X and the negative direction of the Y at 71 ° from the positive x-axis.

5 0
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