Answer:
Time = 2758.62 seconds
Explanation:
Given the following data;
Speed = 290 m/s
Distance = 800 km to meters = 800 * 1000 = 800000
To find the time;
Time = distance/speed
Time = 800000/290
Time = 2758.62 seconds
Therefore, it will take the pilot 2758.62 seconds to reach the airport.
✷ Question: <span>When you stand with the wind blowing on your back, the low pressure center is _____.
Answer: Letter A
</span><span>✐ </span><span>Explanation: When wind hits your back, all the molecules are in front of you.
</span>Hope that helps! ★ If you have further questions or need more help, feel free to comment below or leave me a PM. -UnicornFudge aka Nadia
Answer:
hope you like it
Explanation:
To find velocity, we take the derivative of the original position equation. To find acceleration, we take the derivative of the velocity function. To determine the direction of the particle at t = 1 t=1 t=1, we plug 1 into the velocity function.
According to the conservation of energy
- Potential energy at any given instance is equal to the Kinetic energy as energy can neither be created nor be destroyed
Mass is 2kg=m
#A
h=5m
PE
Now
- KE=98J
- 1/2mv²=98J
- 1/2×2v²=98J
- v²=98J
- v=√98
- v=9.4m/s
#B
h=3.2m
PE:-
Now
- KE=62.7J
- 1/2mv²=62.7
- v²=62.7
- v=√62.7
- v=7.9m/s
#C
h=2m
PE
Now
Answer:
Explanation:
The standard unit of momentum Is kgm/s
And momentum is the product of mass and velocity
Then,
Momentum = mass × velocity
P = mv
Where
m is mass in kg
v is velocity in m/s
Now,
Given that,
M = 31.8mg
1mg = 10^-3g
So, m = 31.8 × 10^-3g
Also, 1000g = 1kg → 1g = 10^-3 kg
So,
m = 31.8 × 10^-3 × 10^-3kg
m = 31.8 × 10^-6 kg
v = 2.53mi/hr
1mile = 1609.34 m
1 hour = 3600seconds
Then,
v = 2.53 × 1609.34m/ 3600s
v = 1.13 m/s
So, momentum is given as
P = mv
P = 31.8 × 10^-6 × 1.13
P = 3.597 × 10^-5 kgm/s