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jeyben [28]
4 years ago
10

An infinite line of charge with charge density λ1 = 0.6 μC/cm is aligned with the y-axis.

Physics
1 answer:
Ganezh [65]4 years ago
8 0

Answer:

1440 × 10⁴ N/C

Explanation:

Data provided in the question:

Charge density λ1 = 0.6 μC/cm = 6 × 10⁻⁵ C/m

a = 7.5 cm = 0.075 m

Now,

Electric field due to a line charge at a distance 'a' is given as:

Ex(P) = \frac{\lambda}{2\pi\epsilon_0a}

also,

we know

\frac{1}{4\pi\epsilon_0} = 9 × 10⁹ Nm²/C²

Thus,

we have

Ex(P) = \frac{2}{2}\times\frac{\lambda}{2\pi\epsilon_0a}=\frac{2\lambda}{4\pi\epsilon_0a}

therefore,

Ex(P) = \frac{2\times6\times10^{-5}\times9\times10^9}{0.075}

= 1440 × 10⁴ N/C

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Complete Question

The diagram of with this question is shown on the first uploaded image

Answer:

The value is  v = -6.543  \^  i + 9.47 \^ j + 0 \^ k

Explanation:

From the question we are told that

   The mass of the rock is  m = 0.250 \ kg

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    The angle the string makes horizontal is  \theta  = 11.9^o

     The angle which the projection of the string onto  the xy -plane makes with the positive x-axis is  \phi = 34.6^o

    The angular velocity of the rock is  w = 2.50 rev/s  = 2.50 * 2\pi  =15.7 \ rad/s

Generally the radius of the circle made by the length of the string is mathematically represented as

               r = L cos(\theta )

=>            r = 0.75  cos(11.9 )

=>            r = 0.734 \ m

Generally the resultant tangential velocity is mathematically represented as

      v__{R}}  = w * r

=>  v__{R}}  = 15.7  *0.734

=>  v__{R}}  =  11.5 \ m/s

Generally the tangential velocity along the x-axis is  

      v_x  = -v__{R}} *  sin(\phi)

=>   v_x  =- 11.5 *  sin(34.6)

=>   v_x  = -6.543 \ m/s

The negative sign show that the velocity is directed toward the negative x-axis

Generally the tangential velocity along the y-axis is  

      v_y = v__{R}} *  cos(\phi)

=>   v_y  = 11.5 *  cos(34.6)

=>   v_y  = 9.47 \ m/s

Generally the tangential velocity along the y-axis is  

      v_z = v__{R}} *  cos(90)

=>   v_z = 0 \ m/s

Generally the tangential velocity at that instant is mathematically represented as

       v = -6.543  \^  i + 9.47 \^ j + 0 \^ k

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A skater of mass 60 kg has an initial velocity of 12 m/s. He slides on ice where the frictional force is 36 N. How far will the
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Answer:

d = 120 [m]

Explanation:

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The mechanical energy is equal to the sum of the potential energy plus the kinetic energy.  As the track is horizontal there is no unevenness, in this way, there is no potential energy.

E₁ + W₁₋₂ = E₂

where:

E₁  = mechanical energy in the initial state [J] (units of Joules)

W₁₋₂ = work done between the states 1 and 2 [J]

E₂  = mechanical energy in the final state = 0

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E₁ = 0.5*m*v²

where:

m = mass = 60 [kg]

v = initial velocity = 12 [m/s]

Now, the work done is given by the product of the friction force by the distance. In this case, the work is negative because the friction force is acting in opposite direction to the movement of the skater.

W₁₋₂ = -f*d

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0.5*m*v² - (f*d) = 0

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If the size of the molecule is more, that is for heavy gases like refrigerants, the ideal gas law deviates due to the fact that, with increase in pressure, the volume of gas can no longer be considered as negligible.

To know more about intermolecular force go here

brainly.com/question/9007693

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