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artcher [175]
3 years ago
11

As an acapulco cliff diver drops to the water from a height of 42.0 m, his gravitational potential energy decreases by 27,500 j.

what is the diver's weight in newtons?
Physics
1 answer:
seraphim [82]3 years ago
3 0

We know that potential energy is simply energy due to position which has the formula:

PE = mass * gravity * height

We know that mass * gravity is weight, therefore:

PE = weight * height

27500 J = weight * 42 m

<span>weight = 654.76 Newtons</span>

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(a) 328.6 kg m/s

The linear impulse experienced by the passenger in the car is equal to the change in momentum of the passenger:

I=\Delta p = m\Delta v

where

m = 62.0 kg is the mass of the passenger

\Delta v is the change in velocity of the car (and the passenger), which is

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So, the linear impulse experienced by the passenger is

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(b) 404.7 N

The linear impulse experienced by the passenger is also equal to the product between the average force and the time interval:

I=F \Delta t

where in this case

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Solving the equation for F, we find the magnitude of the average force experienced by the passenger:

F=\frac{I}{\Delta t}=\frac{328.6 kg m/s}{0.812 s}=404.7 N

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Answer:

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