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luda_lava [24]
3 years ago
12

A minibus drives with a constant speed of 76 miles per hour. How can I travel in 4 hours?

Physics
1 answer:
nikdorinn [45]3 years ago
5 0

Answer:

Answer:

304

Explanation:Answer:

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Why a small car can stop easier than an 18 wheeler while traveling at 70 mph down the interstate?
almond37 [142]
Smaller cars have less momentum than bigger cars. What’s in motion stays in motion but objects with more momentum (can be from weight or from speed but in this case it’s about weight) tend to stay in motion longer.
3 0
2 years ago
A sound source is located somewhere along the x-axis. Experiments show that the same wave front simultaneously reaches listeners
galina1969 [7]

Answer:

Explanation:

As the source is situated on x - axis , it must be situated in between the two listeners .

So the x coordinate of source is

(-7 + 3 )/2

= - 2 m

The equation of the wave- front will be that o a circle having centre at (-2,0)

and radius = distance between -2 and 3 , that is 5 m

equation of circle

=( x+2 )² + y² = 25

It cuts y axis when x = 0

Putting x = 0

4 + y² = 25

y² = 21

y = + √21 , or - √21

7 0
3 years ago
A wave's frequency is 2Hz and its wavelength is 4 m. What is the wave's speed?
icang [17]

Wave speed = (wavelength) x (frequency)

                       =      (4 m)        x  (2 /sec)

                       =               8 m/sec

7 0
3 years ago
QUESTION 3
Alisiya [41]

The force of frictions is opposed to relative motion.

The acceleration of the crate is approximately <u>2.937 m/s²</u>.

Reason:

The given parameters are;

The mass of the wood, m = 100 kg

The force which can move the wood, F = 588 N

Wood on wood static friction, \mu_s = 0.5

Wood on wood kinetic friction, \mu_k = 0.3

Solution;

The force of friction, F_f, acting when the crate is moving is given as

follows;

F_f = m × g × \mu_k

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

Therefore, we have;

F_f = 100 × 9.81 × 0.3 = 294.3

The force of friction, F_f = 294.3 N

The force with which the crate moves, F = 588 - 294.3 = 293.7

The force with which the crate moves, F = 293.7 N

Force = Mass, m × Acceleration, a

a = \dfrac{F}{m}

Therefore;

a = \dfrac{293.7 \ N}{100 \ kg} = 2.937

The acceleration of the crate, a ≈ <u>2.937 m/s²</u>.

Learn more about friction here:

brainly.com/question/94428

8 0
2 years ago
How could you keep an objects acceleration the same if the force acting on the object were double?
Bogdan [553]
You can keep an object's acceleration constant if the force acting on it is double by adding another force going in the opposite direction of the first force. The second force will have to be as strong as the first force was originally in order for the acceleration to be the same. This is the same concept as if you have 2 of something, double it to get 4, and subtract 2 again. You'll end up with the same value you started with.
7 0
3 years ago
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