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dalvyx [7]
3 years ago
9

The molar mass of phosphorus is equal to the mass of 6.02 x 1023 atoms of phosphorus. What is the molar mass of phosphorus, in g

/mol?
5.14
30.97
45.97
90.33
Chemistry
1 answer:
EastWind [94]3 years ago
4 0
If we look at the periodic table, we see that phosphorous has an atomic mass of 30.97. Therefore, it has a molar mass of 30.97 g/mol. The answer is B.
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Give one example each for a binary compound and a ternary compound. (A ternary compound is one that contains three different ele
Sedbober [7]

Answer and Explanation:

BINARY COMPOUND: A binary compound is that compound which is made up of exactly two elements there are a lot binary compound present for example :H_2O, NaCl,NH_3,H_2S etc

TERNARY COMPOUND : A ternary compound is that compound which is made up of exactly three elements there are a lot binary compound present for example : Na_2SO_4,H_2SO_4,CH_3C00H  etc

7 0
3 years ago
For doping silicon with boron, silicon specimen was kept in gaseous atmosphere containing B2O3 that maintained the B concentrati
Kay [80]

Solution :

From Fick's law:

$\frac{D_{AB}}{\Delta z } \times (C_{A1}-C_{A2})=N_a$

Mass balance: Exits = Accumulation

-N_A A = \frac{dm}{dt}

-N_A A = \frac{dVp}{dt}

-N_A A = \frac{dV}{dt}p

-N_A A = \frac{dhA}{dt}

-N_A A = \frac{dh}{dt} \times Ap

From the last step, area cancels out and thus leaves :

-N_A  = \frac{dh}{dt} \times p

So now we can substitute the $N_A$ by the Fick's law

$\frac{D_{AB}}{\Delta z } \times (C_{A1}-C_{A2})=\frac{dh}{dt} p$

Substituting the values we get

$=\frac{-4 \times 10^{-13}}{0.0001} \times (3 \times 10^{26} - C_{A2}) = \frac{dh}{dt} \times 2.46$

$=-4 \times 10^{-9} \times( 3 \times 10^{26} - C_{A2}) = 0.0001 \times 2.46$

$= -7800 \times 4 \times 10^{-9}  \times (3 \times 10^{26}-C_{A2})=0.000246$$=-(3 \times 10^{26}-C_{A2}) = 7.8846 \times 100 \times \frac{1}{69.62} \times 6.022 \times 10^{23}$

$C_{A2} = 6.85 \times 10^{28} \ \text{ boron atoms} /m^3$

3 0
3 years ago
HELP ME PLEASE!!!!!!!!
Licemer1 [7]

The correct answer is “Radiation.”

8 0
3 years ago
Read 2 more answers
Cesium-133 has an atomic number of 55. It has<br> neutrons.
serious [3.7K]
I think 78 hope it’s right
8 0
3 years ago
6) A rectangular fish tank is 70.00 cm long, 300.00 mm wide, and 300.00 m deep.
KATRIN_1 [288]

Answer:

Volume of water it can hold 63000,000 cm³

Mass of water is 63000,000 g.

Explanation:

Given data:

Length of tank  = 70.00 cm

Width of tank = 300.00 mm

Height of tank = 300.00 m

Volume of water it can hold  = ?

Mass of water = ?

Solution:

First of all we will convert the units into same unit.

Width of tank = 300.00 mm × 1 cm / 10 mm = 30 cm

Height of tank = 300.00 m× 100 cm / 1 m = 30000 cm

Volume of water it can hold:

V = l×w×h

V = 70.00 cm × 30 cm × 30000 cm

V = 63000,000 cm³

Mass of water:

Density of water from literature = 1 g/cm³

d = m/v

1 g/cm³ = m/ 63000,000 cm³

m = 63000,000 g

6 0
3 years ago
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