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dalvyx [7]
3 years ago
9

The molar mass of phosphorus is equal to the mass of 6.02 x 1023 atoms of phosphorus. What is the molar mass of phosphorus, in g

/mol?
5.14
30.97
45.97
90.33
Chemistry
1 answer:
EastWind [94]3 years ago
4 0
If we look at the periodic table, we see that phosphorous has an atomic mass of 30.97. Therefore, it has a molar mass of 30.97 g/mol. The answer is B.
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Determine how many formula units are in 2.35 moles of lithium phosphite?
Stells [14]

Answer:

Determine how many formula units are in 2.35 moles of lithium phosphite?

Explanation:

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4 0
3 years ago
What type of reaction is represented by the following equation?
professor190 [17]

Answer: Double replacement reaction

Explanation:

7 0
1 year ago
On July 8th, I will be 8.51472x10^8 seconds old. How old will I be in years? (Assume 365 days in a year.) Group of answer choice
KatRina [158]

Answer:

26.98

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5 0
3 years ago
Determina el grado de pureza de un marmol (CaCO3), si al descomponerse 125 g del mismo se desprenden 20 litros de dióxido de car
jarptica [38.1K]

Answer:

67.8%

Explanation:

La reacción de descomposición del CaCO₃ es:

CaCO₃ → CO₂ + CaO

<em>Donde 1 mol de CaCO₃ al descomponerse produce 1 mol de CO₂ y 1 mol de CaO.</em>

Usando la ley general de los gases, las moles de dioxido de carbono son:

PV = nRT.

<em>Donde P es presión (1atm), V es volumen (20L), n son moles de gas, R es la constante de los gases (0.082atmL/molK) y T es temperatura absoluta (15 + 273.15 = 288.15K). </em>Reemplazando los valores en la ecuación:

PV / RT = n

1atmₓ20L / 0.082atmL/molKₓ288.15K = 0.846 moles

Como 1 mol de CO₂ es producido desde 1 mol de CaCO₃, las moles iniciales de CaCO₃ son 0.846moles.

La masa molar de CaCO₃ es 100.087g/mol. Así, la masa de 0.846moles de CaCO₃ es:

0.846moles ₓ (100.087g / mol) = <em>84.7g de CaCO₃</em>

Así, la pureza del marmol es:

(84.7g de CaCO₃ / 125g) ₓ 100<em> = </em>

<h3>67.8%</h3>
7 0
3 years ago
Calculate the osmotic pressure of 20 m solution of <br> LiCl at 25C
Soloha48 [4]

Answer:

979 atm

Explanation:

To calculate the osmotic pressure, you need to use the following equation:

π = <em>i </em>MRT

In this equation,

-----> π = osmotic pressure (atm)

-----><em> i</em> = van't Hoff's factor (number of dissolved ions)

-----> M = Molarity (M)

-----> R = Ideal Gas constant (0.08206 L*atm/mol*K)

-----> T = temperature (K)

When LiCl dissolves, it dissociates into two ions (Li⁺ and Cl⁻). Therefore, van't Hoff's factor is 2. Before plugging the given values into the equation, you need to convert Celsius to Kelvin.

<em>i </em>= 2                             R = 0.08206 L*atm/mol*K

M = 20 M                    T = 25°C + 273.15 = 298.15 K

π = <em>i </em>MRT

π = (2)(20 M)(0.08206 L*atm/mol*K)(298.15 K)

π = 979 atm

5 0
2 years ago
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