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Yuki888 [10]
3 years ago
12

The double-slit experiment with electrons illustrates the surprising idea that

Physics
1 answer:
Lubov Fominskaja [6]3 years ago
8 0
<h2>Answer: electrons sometimes behave like waves </h2>

The French physicist <em>Louis De Broglie</em> proposed the existence of matter waves, that is to say that <em>all matter has a wave associated with it</em>.  

On the other hand, <em>Heisenberg</em> enunciated the uncertainty principle, which postulates that the fact that each particle has a wave associated with it, imposes restrictions on the ability to determine its position and speed at the same time.  

These postulations were tested with the double slit experiment (<u>formerly applied to photons</u>) applied to electrons, and the result was: electrons (as well as the other particles different from the photons) are able to behave as waves.

You might be interested in
What is the speed vfinal of the electron when it is 10.0 cm from charge 1?
fgiga [73]

Answer:

Two stationary positive point charges, charge 1 of magnitude 3.45 nC and charge 2 of magnitude 1.85 nC, are separated by a distance of 50.0 cm. An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges. What is the speed v(final) of the electron when it is 10.0 cm from

The answer to the question is

The speed v_{final} of the electron when it is 10.0 cm from charge Q₁

= 7.53×10⁶ m/s

Explanation:

To solve the question we have

Q₁ = 3.45 nC = 3.45 × 10⁻⁹C

Q₂ = 1.85 nC = 1.85 × 10⁻⁹ C

2·d = 50.0 cm

a = 10.0 cm

q = -1.6×10⁻¹⁹C

Also initial kinetic energy = 0 and

Initial electric potential energy = k\frac{qQ_1}{d} + k\frac{qQ_2}{d} = kq(\frac{Q_1+Q_2}{d})

Final kinetic energy due to motion = 0.5·m·v²

Final electric potential energy = k\frac{qQ_1}{a} + k\frac{qQ_2}{2d-a} = kq(\frac{Q_1}{a}+\frac{ Q_2}{2d-a})

From the energy conservation principle we have

0+ kq(\frac{Q_1+Q_2}{d})=0.5mv^2+  kq(\frac{Q_1}{a}+\frac{ Q_2}{2d-a})

Solving for v gives

v=\sqrt{\frac{kq(\frac{Q_1+Q_2}{d})-   kq(\frac{Q_1}{a}+\frac{ Q_2}{2d-a})}{0.5m}}

where k = 9.0×10⁹ and m = 9.109×10⁻³¹ kg

gives v =7528188.32769 m/s or 7.53×10⁶ m/s

v_{final} = 7.53×10⁶ m/s

6 0
4 years ago
PLEASE HELP ME WITH THIS
Kitty [74]

Answer:

i think it might be c but i know its not A or B and im

on the fence for D so the best answer would be C

Explanation:

3 0
3 years ago
Which of the following requires freshwater supplies?
Nitella [24]

Agriculture would use fresh water

7 0
3 years ago
A convex, or converging, lens with a focal length of 34 cm is used to observe an image of an apple than is 80 cm away from the l
Hatshy [7]

The image distance is 59.2 cm and the image is real and small.

<h3>Image distance</h3>

The distance of the image formed by the convex or converging lens is determined by applying the following lens equation.

1/f = 1/u + 1/v

where;

  • f is the focal length = 34 cm
  • u is the object distance = 80 cm
  • v is the image distance = ?

1/v = 1/f - 1/u

1/v = 1/34 - 1/80

1/v = 0.0294 - 0.0125

1/v = 0.0169

v = 1/0.0169

v = 59.2 cm

Thus, the image distance is 59.2 cm and the image is real and small.

Learn more about convex lens here: brainly.com/question/10153605

8 0
2 years ago
Read the scenario.
tankabanditka [31]

Answer:

distance = 6 m

Explanation:

- Distance is a scalar quantity (so, only magnitude, no direction), and it is calculated as the scalar sum of all the distances travelled by an object during its motion, regardless of the direction. So, in this problem, the distance covered by the pinecone is

d = 4 m + 2 m = 6 m

- Displacement is a vector quantity (magnitude+direction), and its magnitude is calculate as the distance in a straight line between the final position and the initial position of the object. In this case, the final position is 2 m west and the initial position is 0 m, so the displacement of the pinecone is

d = 2 m west - 0 m = 2 m west

So, a scalar quantity from this scenario is

distance = 6 m

4 0
3 years ago
Read 2 more answers
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