To solve this problem, the dilution equation (M1 x V1 = M2 X V2) must be used. The given values in the problem are M1= 12.0 M, V1= 30 mL, and M2= 0.160 M. To solve for V2,
V2=M1xV1/M2
V2= (12x30)/0.16
V2= 2,250 mL.
The correct answer is 2.25 L.
3rd Answer. Rays reflect in random directions
Answer: C)The smaller the soil particles, the more water and air available for plant growth.
Explanation:
Answer:
V₂ = 22.23 mL
Explanation:
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
Given data:
Initial volume = 25 mL
Initial pressure = 725 mmHg (725/760 =0.954 atm)
Initial temperature = 20 °C (20 +273 = 293 K)
Final pressure = standard = 1 atm
Final temperature = standard = 273.15 K
Final volume = ?
Solution:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 0.954 atm × 25 mL × 273.15 K / 293 K × 1 atm
V₂ = 6514.63 mL . atm . K / 293 K . atm
V₂ = 22.23 mL
Number of moles is found by formula n=mass/molar mass, or m/M. the molar mass is found by adding together the atomic masses of Na and Cl (22.99 + 35.45) to give 58.44 g/mol. Since the mass of NaCl is 75.0g, we find the number of moles as follows:
n = 75.0 / 58.44 = 1.28 mol
