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3 years ago

How do i simplify -10x+10x

Mathematics

1 answer:

USPshnik [31]3 years ago

7 0

Answer:

Step-by-step explanation:

when they have the same variable you can add them together. When adding 10x and --10x, the cancel out (negate) and you are left with 0

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the area of a rectangular volleyball court is 1800 square feet the courts length is twice it width write a system of equations t

Marianna [84]

Answer:

The dimensions of the rectangular volleyball court are 60 ft x 30 ft

Step-by-step explanation:

Let

x ----> the length of rectangular volleyball court

y ---> the width of the rectangular volleyball court

we know that

The area of the rectangular volleyball court is equal to

$A=xy$

$A=1,800\ ft^2$

$1,800=xy$ ----> equation A

$x=2y$ -----> equation B

substitute equation B in equation A

$1,800=(2y)y$

$1,800=2y^2$

Solve for y

Simplify

$900=y^2$

take square root both sides

$y=30\ ft$

<em>Find the value of x</em>

$x=2y$

substitute the value of y

$x=2(30)=60\ ft$

therefore

The dimensions of the rectangular volleyball court are 60 ft x 30 ft

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3 years ago

Can there be more than one point of intersection between the graphs of two linear equations? why or why not?

SOVA2 [1]

No because they are straight lines, they cannot curve to intersect more than once, think of a capital X.

5 0

2 years ago

A new car, valued at $28,000, depreciates at 9% per year. What is the value of the

Black_prince [1.1K]

I believe the answer is $25,480

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2 years ago

Read 2 more answers

PLEASE LOOK AT THE IMAGE. I’m despite. It’s probably easy.

Sloan [31]

Answer:

Correct answer: (x - 10)² + y² = 441 / 4

Step-by-step explanation:

Given:

(a, b) = (10, 0) the coordinates of the center of the circle

(10, 21/2) circle passing through this point

The standard form of the circle equation is:

(x - a)² + (y - b)² = r² where r is radius of the circle

We will replace the given coordinates of the center of the circle and the point it passes through to get the radius of the circle:

(10 - 10)² + (21/2)² = r² ⇒ r² = (21/2)² = 441 / 4

r² = 441 / 4

(x - 10)² + y² = 441 / 4

God is with you!!!

6 0

3 years ago

Find the distance traveled by a particle with position (x, y) as t varies in the given time interval. x = 5 sin2 t, y = 5 cos2 t

rodikova [14]

$\begin{cases}x(t)=5\sin2t\\y(t)=5\cos2t\end{cases}\implies\begin{cases}\frac{\mathrm dx}{\mathrm dt}=10\cos2t\\\frac{\mathrm dy}{\mathrm dt}=-10\sin2t\end{cases}$

The distance traveled by the particle is given by the definite integral

$\displaystyle\int_C\mathrm dS=\int_0^{3\pi}\sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2}\,\mathrm dt$

where $C$ is the path of the particle. The distance is then

$\displaystyle\int_0^{3\pi}\sqrt{100\cos^22t+100\sin^22t}\,\mathrm dt=10\int_0^{3\pi}\mathrm dt=30\pi$

6 0

3 years ago