Answer:
Geothermal power can provide consistent electricity throughout the day and year - continuous baseload power and flexible power to support the needs of variable renewable energy resources, such as wind and solar. Sustainable Investment.
Explanation:
THIS IS WHY WE SHOULD USE GEOTHERMAL ENERGY IN FUTURE
YOU CAN MARK ME AS BRAINIEST IF YOU WANT
Answer:
The right solution is:
(a) 2.87 eV
(b) 1.4375 eV
Explanation:
Given:
Wavelength,
= 433 nm
Potential difference,
= 1.43 V
Now,
(a)
The energy of photon will be:
E = 
= 
or,
= 
= 
(b)
As we know,
⇒ 
By substituting the values, we get
⇒ 
⇒ 
or,
⇒ 
⇒ 
Answer:
With the addition of the pipe we have a greater torque.
Explanation:
We need to complete the description of the problem, searchin in internet we have:
"Sometimes, even with a wrench, one cannot loosen a nut that is frozen tightly to a bolt. It is often possible to loosen the nut by slipping one end of a long pipe over the wrench handle and pushing at the other end of the pipe. With the aid of the pipe, does the applied force produce a smaller torque, a greater torque, or the same torque on the nut?"
With the addition of the pipe we have a greater torque, as it increases the distance or radius of torque.
We know that torque is defined, as the product of force by distance, in this way we have:
T = F * d
where:
T = torque [N*m]
F = force [N]
d = distance [m]
We can see in the above equation, that increasing the distance increases torque proportionally.
Answer:
502000W/m²
Heat flux = 800×50.2/20 =
502000W/m²
Explanation: