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Mashcka [7]
3 years ago
5

Flying against the jetstream, a jet travels 6060 mi in 6 hours. Flying with the jetstream, the same jet travels 10,640 mi in 8 h

ours. What is the rate of the jet in still air and what is the rate of the jetstream?
Physics
1 answer:
Damm [24]3 years ago
5 0

Answer:

Speed of the jet is U = 1170 miles/hr

Speed of the jet stream is V = 160 miles/hr

Explanation:

Let

The speed of the jet = U

The speed of the jet stream = V

Flying speed with the jet stream = U+V

Flying speed against the jet stream = U-V

Now we know that speed = distance / time

Now flying speed with jet stream, U+V = 10640 / 8

                                                                 = 1330 miles/hr   ------(1)

        flying speed against the jet stream, U-V = 6060 / 6

                                                                             = 1010 miles/hr  -----(2)

Therefore, speed of the jet stream,

subtract (2) from (1), we get

( U+V ) - ( U-V ) = 1330-1010

2V = 320

V = 160 miles/hr

Therefore the speed of the jet stream is V = 160 miles/hr

Now from (1), we know

U+V = 1330

U + 160 =1330

U = 1170 miles/hr

Therefore, speed of the jet is U = 1170 miles/hr

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The similarities and the differences between gravitational and electric force are listed below

Explanation:

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- Coloumb's law gives instead the strength of the electrostatic force between two charged objects, which is

F=k\frac{q_1 q_2}{r^2}

where:

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r is the separation between the two charges

By comparing the two equations, we find the following similarities:

  • Both the forces are inversely proportional to the square of the distance between the two objects, F\propto \frac{1}{r^2}
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Instead, we have the following differences:

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Learn more about gravitational force and electric force:

brainly.com/question/1724648

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brainly.com/question/8960054

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Explanation:

Step 1: Calculate
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KE=.5*600*35.2²

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Suppose Mary would like to design an emergency overheating alarm using one of these materials. In her design, at room temperatur
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Answer:

A. 92.88 °C

B. 401.535 °C

Explanation:

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Where α is a coefficient of linear expansion. For a cylinder made from polycarbonate α = 70,2*10^(-6)  °C^(-1) and for a cylinder made from cast iron α = 12*10^(-6)  °C^(-1). If we isolate the term of the temperature’s difference, we have:

∆L/(L_i * α) = ∆T → T_f = T_i + ∆L/(L_i * α)

Replacing the values, for the case of the Polycarbonate we have:

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Replacing the values, for the case of the Cast Iron we have:

T_f = T_i +∆L/(L_i * α) = 23°C + 0,0273cm/(6,01cm * 12 * 10^(-6) °C^(-1) ) = 401,535 °C

As we see, is way better to use the polycarbonate in this application.

Have a nice day. Let me know if I can help you with anything else. :D

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