The vertex of a parabola is at $(12, -4)$, and its axis of symmetry is vertical. One of the $x$-intercepts is at $(15, 0)$. What

Question

wel

3 years ago

6

The vertex of a parabola is at $(12, -4)$, and its axis of symmetry is vertical. One of the $x$-intercepts is at $(15, 0)$. What

is the $x$-coordinate of the other $x$-intercept?

Mathematics

1 answer:

laila [671] · Answer 1 · 2022-01-11T19:52:37+03:00

Answer:

9

Step-by-step explanation:

Since the axis of symmetry is vertical and the vertex of the parabola is at (12,-4), the vertical line x=12 is the axis of symmertry. The x-distance between the axis of symmetry and the first x intercept (15,0) is equal to 15-12=3. Hence, this x-intercept is 3 units to the right of the axis, and because it is symmetric, the other x-intercept must be 3 units to the left of the axis, so its x-coordinate must be 12-3=9. Then, the other x-intercept is at the point (9,0)