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Advocard [28]
3 years ago
6

Assume you are working for a chemical company and are responsible for growing a yeast culture that produces ethanol. The yeasts

are growing well on the maltose medium but are not producing alcohol. What is the most likely explanation?
Chemistry
1 answer:
romanna [79]3 years ago
6 0

Answer:

Respiration might occur in the presence and absence of oxygen known as the aerobic respiration and anaerobic respiration. The ATP molecules are produced more in number in aerobic respiration.

The yeast has the ability to undergo the process of anaerobic respiration and its end product are alcohol, carbon dioxide and 2 moles of ATP. The yeast is grown on maltose medium but unable to produce alcohol because of the presence of oxygen in the medium. The oxygen might acts as poison or inhibit the process of anaerobic respiration.

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Consider the balanced equation below.
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The correct option is (a) H₂S : SO₂ = 2 : 2 and O₂ : H₂O = 3 : 2

<h3>What is molar Ratio ?</h3>

Molar ratio also known as stoichiometry is the ratio in which the reactants and products are either formed or reacted in the given equation

the balanced equation is as follows ;

2H₂S + 3O₂ --> 2SO₂ + 2H₂O

molar ratio can be determined by the coefficients of the compounds in the balanced reaction.

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coefficients for the compounds in this reaction are as follows ;

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brainly.com/question/17920577

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3 years ago
The volume of a sample gas, initially at 25 C and 158 mL, increased to 450 mL. What is the final temperature of the sample of ga
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Final temperature of the gas is  576 ^{0}\textrm{C}.

Explanation:

As the amount of gas and pressure of the gas remains constant therefore in accordance with Charles's law:

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where V_{1} and V_{2} are volume of gas at T_{1} and T_{2} temperature (in kelvin scale) respectively.

Here V_{1}=158mL , T_{1}=(273+25)K=298K and V_{2}=450mL

So  T_{2}=\frac{V_{2}T_{1}}{V_{1}}=\frac{(450mL)\times (298K)}{(158mL)}=849K 

849 K = (849-273) ^{0}\textrm{C} = 576 ^{0}\textrm{C}

So final temperature of the gas is  576 ^{0}\textrm{C}.

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