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Explanation:
Given that,
Induced emf
Rate of current = 0.250 A/s
Number of turns =30
(a). We need to calculate the mutual inductance of the pair of coils
Using formula of the mutual inductance
The mutual inductance of the pair of coils is 6.6 mHz.
(b). We need to calculate the flux through each turn
Using formula of flux
Put the value into the formula
The flux through each turn is
(c). We need to calculate the magnitude of the induced emf in the first coil
Using formula of induced emf
The magnitude of the induced emf in the first coil is
Hence, This is the required solution.
Answer:
speed = 1.24 × 10⁸m/s
frequency = 4.74 × 10¹⁴Hz
wavelength = 262nm
Explanation:
the speed of the helium-neon light in zircon is given by,
v = c / n
c = 3 × 10⁸m/s is the speed of light in vacuum (and in air)
n = 2.419 is the refractive index of diamond
v = 3 × 10⁸ / 2.419
= 1.24 × 10⁸m/s
(b) Frequency
The wavelength of the light in air is:
λ₀ = 632.8 × 10⁻⁹
The frequency of the light does not depend on the medium, so it is equal in air and in diamond. Therefore, we can calculate the frequency by using the speed of light in air and the wavelength in air:
f₀ = c / λ₀
= 3 × 10⁸ / 632.8 × 10⁻⁹
= 4.74 × 10¹⁴Hz
and the frequency of the light indiamond is the same:
f¹ = f₀ = 4.74 × 10¹⁴Hz
(c) Wavelength
To calculate the wavelength of the light in daimond, we can use the relationship between speed of light in diamond and frequency:
λ¹ = v / f¹
= 1.24 × 10⁸ / 4.74 × 10¹⁴
= 2.62 × 10⁻⁷m
= 262nm
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