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IrinaVladis [17]
3 years ago
15

A bicycle starts at 2.5m/s and accelerates along a straight path to a speed of 12.5m/s in a time of 4.5 seconds. What is the bic

yclist’s acceleration to the nearest tenth of a m/s^2 ?
Physics
1 answer:
zalisa [80]3 years ago
3 0

Answer:

The bicyclist's acceleration is 2.2m/s^2

Explanation:

Given

u = 2.5m/s ---- Initial Velocity

v = 12.5m/s ---- Final Velocity

t = 4.5s ---- Time

Required

Determine the acceleration

This will be solved using the first equation of motion

v = u + at

Substitute values for v, u and a

12.5 = 2.5 + a * 4.5

12.5 = 2.5 + 4.5a

Collect Like Terms

4.5a = 12.5 - 2.5

4.5a = 10.0

Solve for a

a = 10.0/4.5

a = 2.2m/s^2 ---- (approximated)

<em>Hence, the bicyclist's acceleration is 2.2m/s^2</em>

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