Answer:
Angular velocity is same as frequency of oscillation in this case.
ω = 
x ![[\frac{L^{2}}{mK}]^{3/14}](https://tex.z-dn.net/?f=%5B%5Cfrac%7BL%5E%7B2%7D%7D%7BmK%7D%5D%5E%7B3%2F14%7D)
Explanation:
- write the equation F(r) = -K
with angular momentum <em>L</em>
- Get the necessary centripetal acceleration with radius r₀ and make r₀ the subject.
- Write the energy of the orbit in relative to r = 0, and solve for "E".
- Find the second derivative of effective potential to calculate the frequency of small radial oscillations. This is the effective spring constant.
- Solve for effective potential
- ω = x
Lighting flows around the outside of a truck, and the majority of the current flows from the cars metal cage into the ground below. It's not very safe to be in a car or truck during bad weather.
Answer:
c
Explanation:
The car travels with centripetal acceleration which is directed to the center of the circle but the velocity is changing since the car faces different direction as it travels in the circular direction. When the friction is zero between the tires of the car and the road, it will continue in the direction of its tangential velocity which will be along a straight-line path in its original direction.
The equation that describes the graph is y = 16.7x + 150.
<h3>What is the equation?</h3>
We have been given the graph of a certain function data set in physics. We know that the graph is the representation of data on cartesian coordinates. In this case, we are asked to find the equation of the graph in the form; y=mx+b
m = slope of the graph
b = intercept of the graph.
To obtain the slope;
m = y2 - y1/ x2 - x1
m = 400 - 200/ 16 - 4
m = 200/ 12
m = 16.7
Then we can see from the graph that the y - intercept is 150. Having these data, the equation that could describe the graph is now;
y = 16.7x + 150
Learn more about graph:brainly.com/question/13301664
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