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Mandarinka [93]
3 years ago
12

Which gas is used to take out blueprint​

Chemistry
1 answer:
tiny-mole [99]3 years ago
7 0

The blueprint process

The best known is a process using ammonium ferric citrate and potassium . The paper is impregnated with a solution of ammonium ferric citr

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How many moles of na contain 7.88x1021 atoms of na
labwork [276]

Answer:

the answer to the qustion is 0.013089701 na

Explanation:

n/a

7 0
2 years ago
Given the following reaction: \ce{Cu + 2AgNO3 -> 2Ag + Cu(NO3)2}Cu+2AgNO3 ​ ​ 2Ag+Cu(NOX 3 ​ )X 2 ​ How many moles of \ce{Ag}
Alexandra [31]

Answer:

0.252 mol

Explanation:

<em>Given the following reaction: </em>

<em>Cu + 2 AgNO₃ → 2 Ag + Cu(NO₃)₂</em>

<em>How many moles of Ag will be produced from 16.0 g Cu, assuming AgNO3 ​ is available in excess.</em>

First, we write the balanced equation.

Cu + 2 AgNO₃ → 2 Ag + Cu(NO₃)₂

We can establish the following relations.

  • The molar mass of Cu is 63.55 g/mol.
  • The molar ratio of Cu to Ag is 1:1.

The moles of Ag produced from 16.0 g of Cu are:

16.0gCu.\frac{1molCu}{63.55gCu} .\frac{1molAg}{1molCu} =0.252 molAg

6 0
3 years ago
Read 2 more answers
How many liters of ammonia gas can be formed from 54.1 liters of hydrogen
Aleks04 [339]
 <span>The reaction is N2 + 3H2 -> 2NH3 
So the amount of NH3 formed is 2/3 of the amount of H2 = 2/3 * 13.7 = 9.13 Liters.</span><span>The answer is 9.13

</span>
5 0
3 years ago
What is the mass of 8.12 × 10^23 molecules of CO2 gas? (Atomic mass of carbon = 12.011 u; oxygen = 15.999 u.)
amid [387]

Answer:

m=59.3gCO_2

Explanation:

Hello,

In this case, the first step is to compute the molar mass of carbon dioxide as shown below, considering it has one carbon atom and two oxygen atoms:

M=12.011g/mol+2*15.999g/mol\\\\M=44.009g/mol

It is important to notice it is the mass in one mole of such compound. Afterwards, we need to use the Avogadro's number to compute the how many moles are in the given molecules of carbon dioxide as shown below:

mol=8.12x10^{23}molec*\frac{1mol}{6.022x10^{23}molec} =1.35mol

Finally, the mass by using the molar mass:

m=1.35mol*\frac{44.009g}{1mol} \\\\m=59.3gCO_2

Best regards.

4 0
3 years ago
Is MgCO3 organic or inorganic
schepotkina [342]
Its inorganic as MgCO3 is contains no carbon more hydrogen which is a crutial component of all organic compounds 
4 0
3 years ago
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