Answer:
24+74+61+29+38+27+68+54= 375
then divide by the number of numbers in this case 8 so;
375/8= 46.875
<h2>that's the median
46.875</h2>
Explanation:
Answer:
A; 
Explanation:
The best way to start solving this problem is to start with the molecule with the most atoms. Since there are 12 carbons on the left, you need 12 on the right so 12 would need to be placed in front of carbon dioxide. Also you need 22 hydrogens and in each molecule of water, there are two hydrogen molecules so you need 11 molecules of water. After balancing you find that you need 24 oxygen on the left so you place the coeffecient 12 in front of the oxygen molecule.
Answer:
Mass = 182.4 g
Explanation:
Given data:
Number of moles of Al₂O₃ = 3.80 mol
Mass of oxygen required = ?
Solution:
Chemical equation:
4Al + 3O₂ → 2Al₂O₃
Now we will compare the moles of aluminum oxide and oxygen.
Al₂O₃ : O₂
2 : 3
3.80 : 3/2×3.80 = 5.7
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 5.7 mol × 32 g/mol
Mass = 182.4 g
26.5 g of Fe₂(SO₄)₃
Explanation:
We have the following chemical reaction:
2 FePO₄ + 3 Na₂SO₄ → Fe₂(SO₄)₃ + 2 Na₃PO₄
number of moles = mass / molecular wight
number of moles of FePO₄ = 20 / 151 = 0.1325 moles
Taking in account the chemical reaction we devise the following reasoning:
if 2 moles of FePO₄ produces 1 mole of Fe₂(SO₄)₃
then 0.1325 moles of FePO₄ produces X moles of Fe₂(SO₄)₃
X = (0.1325 × 1) / 2 = 0.06625 moles of Fe₂(SO₄)₃
mass = number of moles × molecular wight
mass of Fe₂(SO₄)₃ = 0.06625 × 400 = 26.5 g
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number of moles
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Answer:work function= 8.2×10-19J
Minimum wavelength of light required= 2.4×10-7m
Explanation:
The wavelength of incident light was given as 193nm. We have to convert this to meters and have 193×10-9m. Then we use it to find the energy of incident photon E. When E is found we now apply Einstein photoelectric equation to obtain the work function Wo since the kinetic energy of photoelectrons is known as 1.8×10-19J.
From this work function. We can obtain the minimum wavelength of light required. All these steps are shown in the image attached.